我必須發(fā)布用戶名、密鑰和另一個(gè)參數(shù)才能將數(shù)據(jù)作為 JSONObject 獲取并在 RecyclerView 中顯示它們。我在 android 中使用 Volley Library，嘗試了所有可能的方法，但沒有一個(gè)有幫助。即使通過 Postman 進(jìn)行測(cè)試似乎工作正常，并且當(dāng)我發(fā)布這三個(gè)參數(shù)時(shí)我得到了數(shù)據(jù)，但我不知道我錯(cuò)過了什么安卓..PHP代碼：<?phprequire("db/Db.class.php");if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getMainCategory'])){ $db = new DB(); $username = $_POST['username']; $key = $_POST['key']; $query = $db->query("SELECT * FROM oc_api where `username` = '$username' and `key` = '$key' limit 1 "); if(count($query) == 0){ $json = ["error don't have permittion"]; }else{ $catigory = $db->query("SELECT * FROM `oc_category_description`,oc_category WHERE oc_category_description.category_id = oc_category.category_id and oc_category.status = 1 and oc_category.parent_id = 0 and oc_category_description.language_id = 2"); $json = $catigory; } header('Content-Type: application/json'); echo json_encode($json); return;}if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getSlideShow'])){ $db = new DB(); $username = $_POST['username']; $key = $_POST['key']; $slideShowId = (int)$_POST['getSlideShow']; $query = $db->query("SELECT * FROM oc_api where `username` = '$username' and `key` = '$key' limit 1 "); if(count($query) == 0){ $json = ["error don't have permittion"]; }else{ $banderSlideShow = $db->query("SELECT * FROM `oc_banner_image` where `banner_id` = $slideShowId and language_id = 2"); $json = $banderSlideShow; } header('Content-Type: application/json'); echo json_encode($json); return;}if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getAllNews'])){ $db = new DB(); $username = $_POST['username']; $key = $_POST['key']; $query = $db->query("SELECT * FROM oc_api where `username` = '$username' and `key` = '$key' limit 1 "); if(count($query) == 0){ $json = ["error don't have permittion"]; }
3 回答
MMMHUHU
TA貢獻(xiàn)1834條經(jīng)驗(yàn) 獲得超8個(gè)贊
您已經(jīng)完成了所有代碼，并且在發(fā)送響應(yīng)之前設(shè)置了 json=["error"];
[不要忘記接受答案并在答案正確的情況下點(diǎn)贊或闡明（更多解釋）您的問題，以便回答者可以給出更相關(guān)的答案]
<?php
require("db/Db.class.php");
if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getMainCategory'])){
//your code
//remove below two lines from every if as it can be called commonly at last;
//header('Content-Type: application/json');
//echo json_encode($json);
}else if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getSlideShow'])){
//your code
}else if(isset($_POST['key']) && isset($_POST['username']) && isset($_POST['getAllNews'])){
//your code
}else{
$json = ["error"];
}
header('Content-Type: application/json');
echo json_encode($json);
?>
慕標(biāo)5832272
TA貢獻(xiàn)1966條經(jīng)驗(yàn) 獲得超4個(gè)贊
我解決了這個(gè)問題，實(shí)際上這很荒謬。在第一個(gè) params.put 中，“用戶名”旁邊有一個(gè)小空間，這導(dǎo)致了這個(gè)問題，沒有獲取數(shù)據(jù)，也導(dǎo)致了異常。即使我仔細(xì)檢查了，但沒有不知道我是怎么錯(cuò)過的……感謝所有花時(shí)間幫助我的人。我很感激。
@Override
protected Map<String,String> getParams(){
Map<String,String> params = new HashMap<String, String>();
//the line below was causing the exception. right side of "username " (space)
params.put("username ",user);
params.put("key",api);
params.put("getMainCategory",no);
return params;
}
慕哥6287543
TA貢獻(xiàn)1831條經(jīng)驗(yàn) 獲得超10個(gè)贊
由于您期待 JSONArray，因此不要選擇 StringRequest，而是使用 volley 中可用的 JsonArrayRequest。請(qǐng)參閱此文檔： https: //developer.android.com/training/volley/request
您的錯(cuò)誤日志也表明
java.lang.String 無法轉(zhuǎn)換為 JSONObject
因此我建議你試試這個(gè)：
JsonArrayRequest req = new JsonArrayRequest(Request.Method.POST, URL_PRODUCTS,
new Response.Listener<String>() {
@Override
public void onResponse(JSONArray response) {
//.............
因?yàn)槟闫诖粋€(gè) json 數(shù)組。
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