我想做的是所以我基本上想做的是每次一輛車越過(guò)終點(diǎn) 它說(shuō)哪輛車有一個(gè)但我想做的是每次第一輛車獲勝并且第二輛車越過(guò)終點(diǎn)線我想要它說(shuō)哪輛車排在第二位和第三位等等import pygame, randompygame.init()# musicmusic = pygame.mixer.music.load(“image/Led Zeppelin - Rock And Roll (Alternate Mix) (Official Music Video).mp3”)pygame.mixer.music.play(-1)#Setting up our colors that we are going to useGREEN = (20, 255, 140)GREY = (210, 210, 210)WHITE = (255, 255, 255)RED = (255, 0, 0)PURPLE = (255, 0, 255)BLACKWHITE =(96, 96, 96)SCREENWIDTH = 400SCREENHEIGHT = 500size = (SCREENWIDTH, SCREENHEIGHT)screen = pygame.display.set_mode(size)pygame.display.set_caption("Car Racing")Icon = pygame.image.load("image/redca_iconr.png")pygame.display.set_icon((Icon))# This will be a list that will contain all the sprites we intend to use in our game.#all_sprites_list = pygame.sprite.Group()#playerplayerIMG = pygame.image.load("image/red_racecar.png")playerX = 250playerY = 450playerCar_position = 0#player2playerIMG_two = pygame.image.load("image/greencar.png")playerX_two = 150playerY_two = 450playerCar_position_two = 0#player3playerIMG_three = pygame.image.load("image/Orangecar.png")playerX_three = 50playerY_three = 450playerCar_position_three = 0#player4playerIMG_four = pygame.image.load("image/yellow_car.png")playerX_four = 200playerY_four = 450playerCar_position_four = 0#Putting cars to the screendef player(x, y): screen.blit(playerIMG, (x, y))def player_two(x, y): screen.blit(playerIMG_two, (x, y))def player_three(x, y): screen.blit(playerIMG_three, (x, y))def player_four(x, y): screen.blit(playerIMG_four, (x, y))
2 回答
哈士奇WWW
TA貢獻(xiàn)1799條經(jīng)驗(yàn) 獲得超6個(gè)贊
所以，你得到的代碼有效，唯一的問(wèn)題是當(dāng)汽車與終點(diǎn)線相交時(shí)，你只在屏幕上顯示文本
因此，每幀都有一個(gè)字符串放在屏幕上，當(dāng)汽車越過(guò)這條線時(shí)，將字符串更改為那輛車
#put these outside the game loop
finish_text = ""
font2 = pygame.font.SysFont("Papyrus", 45)
players_finished = 0
placings = ["1st", "2nd", "3rd", "4th"]
while running: #game loop
...
# Did anyone cross the line?
if (finish_line_rect.collidepoint(playerX, playerY)):
if finish_text[:9] != "Player 1": #so it doesnt do this every frame the car is intersecting
finish_text = "Player 1 is " + placings[players_finished]
players_finished += 1
print("Player (one) has crossed into finish line!")
elif (finish_line_rect.collidepoint(playerX_two , playerY_two)):
if finish_text[:9] != "Player 2":
print("Player one has crossed into finish line first other car lost!")
finish_text = "Player 2 is " + placings[players_finished]
players_finished += 1
elif (finish_line_rect.collidepoint(playerX , playerY)):
if finish_text[:9] != "Player 3":
print("Player two has crossed into finish line first other car lost!")
finish_text = "Player 3 is " + placings[players_finished]
players_finished += 1
elif (finish_line_rect.collidepoint(playerX_two, playerY_two)):
if finish_text[:9] != "Player 4":
print("Player two has crossed into finish line first other car lost!")
finish_text = "Player 4 is " + placings[players_finished]
players_finished += 1
if finish_text != "": #test to see if there is anything to put on screen
text2 = font2.render(finish_text, 5, (255, 99, 7))
screen.blit(text2, (135 - (text2.get_width() / 5), 95))
pygame.display.flip()
筆記。還沒(méi)有測(cè)試過(guò)
UYOU
TA貢獻(xiàn)1878條經(jīng)驗(yàn) 獲得超4個(gè)贊
我從未使用過(guò) pygame，所以不知道是否有內(nèi)置函數(shù)。但是，您可以輕松地制作一個(gè)計(jì)數(shù)器。
#this is all in your while loop
if playerY<50 or playerY_two<50 or playerY_three<50 or playerY_four<50:
count+=1
if count == 1:
if playerY<50:
print('playerY first place')
playerY=10000
if playerY_two<50:
print('playerY_two first place')
playerY_two=100000
if playerY_three<50:
print('playerY_three first place')
playerY_three=100000
if playerY_four<50:
print('playerY_four first place')
playerY_four=1000000
if count == 2:
if playerY<50:
print('playerY second place')
playerY=10000
if playerY_two<50:
print('playerY_two seoncd place')
playerY_two=100000
if playerY_three<50:
print('playerY_three second place')
playerY_three=100000
if playerY_four<50:
print('playerY_four second place')
playerY_four=1000000
if count == 3:
if playerY<50:
print('playerY third place')
playerY=10000
if playerY_two<50:
print('playerY_two third place')
playerY_two=100000
if playerY_three<50:
print('playerY_three third place')
playerY_three=100000
if playerY_four<50:
print('playerY_four third place')
playerY_four=1000000
if count == 4:
if playerY<50:
print('playerY 4th place')
playerY=10000
if playerY_two<50:
print('playerY_two 4th place')
playerY_two=100000
if playerY_three<50:
print('playerY_three 4th place')
playerY_three=100000
if playerY_four<50:
print('playerY_four 4th place')
playerY_four=1000000
break
你可以創(chuàng)建一個(gè)類/函數(shù)來(lái)將上面的全部?jī)?nèi)容寫成 4 行到 5 行，但一般的想法是你想打印出誰(shuí)越過(guò)終點(diǎn)線，但你只希望打印一次。
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