我有一個命名元組列表如下record = [({ "first_name":"nadbor", "last_name":"drozd", "occupation":"data scientist", "markingAgentUsed":[ { "consumableLabelCode":"L", "amountUsed":{ "amount" : 100, "unit": "litre" } }, { "consumableLabelCode":"Y", "amountUsed":{ "amount" : 300, "unit": "mililitre" } }, { "consumableLabelCode":"0", "amountUsed":{ "amount" : 999, "unit": "gallon" } } ]})][{'first_name': 'nadbor', 'last_name': 'drozd', 'occupation': 'data scientist', 'markingAgentUsed': [{'consumableLabelCode': 'L', 'amountUsed': {'amount': 100, 'unit': 'litre'}}, {'consumableLabelCode': 'Y', 'amountUsed': {'amount': 300, 'unit': 'mililitre'}}, {'consumableLabelCode': '0', 'amountUsed': {'amount': 999, 'unit': 'gallon'}}]}]我想根據(jù) LabelCode 的輸入?yún)?shù)提取值，我想提取兩個值 amount 和 unit。例如，如果我通過 O，我應該得到 999 和加侖作為輸出。
2 回答
青春有我
TA貢獻1784條經(jīng)驗 獲得超8個贊
record = [({
"first_name":"nadbor",
"last_name":"drozd",
"occupation":"data scientist",
"markingAgentUsed":[
{
"consumableLabelCode":"L",
"amountUsed":{
"amount" : 100,
"unit": "litre"
}
},
{
"consumableLabelCode":"Y",
"amountUsed":{
"amount" : 300,
"unit": "mililitre"
}
},
{
"consumableLabelCode":"0",
"amountUsed":{
"amount" : 999,
"unit": "gallon"
}
}
]
})]
userKey = '0'
for entry in record[0]['markingAgentUsed']:
if entry['consumableLabelCode'] == userKey:
print("Amount - {}".format(entry['amountUsed']['amount']) )
print("Units - {}".format(entry['amountUsed']['unit']) )
四季花海
TA貢獻1811條經(jīng)驗 獲得超5個贊
這一切都是關于理解數(shù)據(jù)結構的嵌套（這不是一個命名的元組，而是一個字典元組列表和一個字典列表，其中一些鍵本身就是字典：-/很少！這段代碼提取了你的內(nèi)容要求：
inp = '0'
for ma in record[0]['markingAgentUsed']:
if ma['consumableLabelCode'] == inp:
print(ma['amountUsed']['amount'], ma['amountUsed']['unit'])
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