我正在使用改造從服務(wù)器獲取數(shù)據(jù)。我想從我的 arrayList 中獲取最后一個(gè)元素，該怎么做？我已經(jīng)閱讀了如何從這個(gè)問(wèn)題中獲取最后一個(gè)元素 如何獲取 ArrayList 的最后一個(gè)值，但它不起作用。這是我的 JSON 對(duì)象http://ipsta.tech/koor.php這是我的適配器類 private Context context; public KinectAdapter(List<Koor> koorList, Context context) { this.koorList = Collections.singletonList(koorList); this.context = context; } @Overridepublic ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) { View view = LayoutInflater.from(context).inflate(R.layout.kinect,parent,false); return new ViewHolder(view); }@Overridepublic void onBindViewHolder(ViewHolder holder, int position) { holder.x.setText(String.valueOf(koorList.get(position).getX())); holder.y.setText(String.valueOf(koorList.get(position).getY()));}@Overridepublic int getItemCount() { return koorList.size(); }public static class ViewHolder extends RecyclerView.ViewHolder{ public TextView x,y; public ViewHolder(View itemView) { super(itemView); x = (TextView) itemView.findViewById(R.id.tvX); y = (TextView) itemView.findViewById(R.id.tvY); }}
2 回答
幕布斯7119047
TA貢獻(xiàn)1794條經(jīng)驗(yàn) 獲得超8個(gè)贊
onResponse在改造電話中使用它
call.enqueue(new Callback<List<Koor>>() {
@Override
public void onResponse(Call<List<Koor>> call, Response<List<Koor>> response)
{
koorArrayList = response.body();
Koor mKoor = koorArrayList.get(koorArrayList.size() - 1);
}
..............
在mKoor你有來(lái)自 Koor List 的最后一個(gè) Koor 對(duì)象
波斯汪
TA貢獻(xiàn)1811條經(jīng)驗(yàn) 獲得超4個(gè)贊
你可以做到Arraylist.size()
@Override
public void onResponse(Call<List<Koor>> call, Response<List<Koor>> response) {
koorArrayList = response.body();
Koor e = koorArrayList.get(koorArrayList.size() - 1);
}
或者您可以簡(jiǎn)單地訪問(wèn)您的適配器
@Override
public void onBindViewHolder(ViewHolder holder, int position) {
--------******************---------------------
Koor e = koorList.get(koorList.size() - 1);
--------******************---------------------
holder.x.setText(String.valueOf(koorList.get(position).getX()));
holder.y.setText(String.valueOf(koorList.get(position).getY()));
}
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