假設(shè)我有一個關(guān)鍵詞列表：terms = ["dog","cat","fish"]我還有另一個列表，其中包含更長的文本字符串：texts = ["I like my dog", "Hello world", "Random text"]我現(xiàn)在想要我有一個代碼，它基本上遍歷列表texts并檢查它是否包含列表中的任何項目terms，并且它應(yīng)該返回一個列表，其中包含文本中的此項是否匹配。這是代碼應(yīng)該產(chǎn)生的：result = ["match","no match","no match"]
1 回答
夢里花落0921
TA貢獻1772條經(jīng)驗 獲得超6個贊
以下是如何使用zip()和列表理解：
terms = ["dog","cat","fish"]
texts = ["I like my dog", "Hello world", "Random text"]
results = ["match" if a in b else "no match" for a,b in zip(terms,texts)]
print(results)
輸出：
['match', 'no match', 'no match']
更新：結(jié)果證明壓縮不是 OP 想要的。
terms = ["dog","cat","fish"]
texts = ["I like my dog", "Hello world", "Random text"]
results = ["match" if any(b in a for b in terms) else "no match" for a in texts]
print(results)
輸出：
['match', 'no match', 'no match']
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