std::unique_lock<std::mutex>my_lc(my_mutex);my_cond.wait_for(my_lc, std::chrono::milliseconds(10000));
2 回答
慕姐8265434
TA貢獻(xiàn)1813條經(jīng)驗(yàn) 獲得超2個(gè)贊
根據(jù)c++源碼看，超時(shí)后會(huì)退出阻塞，繼續(xù)執(zhí)行后續(xù)代碼
template <class Rep, class Period>
cv_status wait_for (unique_lock<mutex>& lck,
const chrono::duration<Rep,Period>& rel_time);
return wait_until (lck,chrono::steady_clock::now() + rel_time, std::move(pred));
帶謂詞
template <class Rep, class Period, class Predicate>
bool wait_for (unique_lock<mutex>& lck,
const chrono::duration<Rep,Period>& rel_time, Predicate pred);
while (!pred())
if (wait_until(lck,abs_time) == cv_status::timeout)
return pred();//超時(shí)后調(diào)用謂詞并返回結(jié)果，true or false
return true;
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