我有下面的數(shù)組 Array ( [0] => Array ( [group_description] => Group 1 [services] => Array ( [0] => Array ( [service_id] => 1 [service_name] => Security [service_total] => 10 ) [1] => Array ( [service_id] => 4 [service_name] => Catering [service_total] => 20 ) ) ) [1] => Array ( [group_description] => Group 2 [services] => Array ( [0] => Array ( [service_id] => 1 [service_name] => Security [service_total] => 6 ) [1] => Array ( [service_id] => 4 [service_name] => Catering [service_total] => 15 ) [2] => Array ( [service_id] => 5 [service_name] => Lighting [service_total] => 8 ) ) ) )我想對具有相同服務(wù)的數(shù)組求和并創(chuàng)建一個總數(shù)組并像這樣放回數(shù)組 我試過循環(huán)數(shù)組并在循環(huán)時創(chuàng)建一個新數(shù)組。我使用了一個 foreach 循環(huán)，然后使用 array_search 函數(shù)來查看我在忙于哪個并追加到新數(shù)組。但它沒有達(dá)到我想要的效果，我總是以相同的數(shù)組結(jié)束。就像我真的陷入了一個循環(huán)。我看過很多例子，但我認(rèn)為我的案例與例子不相似
1 回答
至尊寶的傳說
TA貢獻(xiàn)1789條經(jīng)驗(yàn) 獲得超10個贊
你需要超過 1 個 foreach。每次最深的迭代檢查是否添加了服務(wù)。如果是，則添加當(dāng)前值，如果不是，則添加整個服務(wù)。最后加入當(dāng)前數(shù)組。
function count_services($array)
{
$service_list = [];
foreach ($array as $row) {
foreach ($row['services'] as $service) {
if (isset($service_list[$service['service_id']])) {
$service_list[$service['service_id']]['service_total'] += $service['service_total'];
} else {
$service_list[$service['service_id']] = $service;
}
}
}
return [
'group_description' => 'Total',
'services' => array_values($service_list)];
}
print_r(count_services($array));
輸出：
Array
(
[group_description] => Total
[services] => Array
(
[0] => Array
(
[service_id] => 1
[service_name] => Security
[service_total] => 16
)
[1] => Array
(
[service_id] => 4
[service_name] => Catering
[service_total] => 35
)
[2] => Array
(
[service_id] => 5
[service_name] => Lighting
[service_total] => 8
)
)
)
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