const json = [{  "order": 1111,  "items": [    {      "colour1": "red",      "colour2": "yellow",    },    {      "colour1": "red",      "colour2": "red",    },    {      "colour1": "red",      "colour2": "red",    }  ]},{  "order": 2222,  "items": [    {      "colour1": "black",      "colour2": "blue",      "colour3": "orange"    },    {      "colour1": "white",      "colour2": "red",      "colour3": "green",          }  ]}]Object.entries(json).forEach(([i, v]) => {    let count = [];    Object.entries(v.items).forEach(([j, k]) => {        if (k.colour2.includes('red')) {            count.push(k.colour2)        }    });    console.log(count, count.length) //length = [2, 1]});我覺得我寫的這段代碼不是過(guò)濾和計(jì)算長(zhǎng)度的有效方法。目標(biāo)是過(guò)濾某個(gè)值并得到結(jié)果。尋找替代方法和正確的 es6 方法來(lái)做到這一點(diǎn)。謝謝