我希望將“波浪”模式打印到控制臺，例如： /\ / \ / 或者： /\ / \ \ \最后，顯示為一個大的多波： /\ /\ / \/ \ / \ \基于描述向上/向前或向下/向后方向/斜線中斜線數(shù)量的整數(shù)列表。我定義了兩個函數(shù)，一個用于波的左側(cè)最長，反之亦然：from itertools import zip_longestdef left_wave(water_l, water_r): """When left side of wave is largest""" l_str = " " * water_l + "/" if water_r == 1: r_str = "\\" elif water_r: r_str = " " * (water_r * 2 - 2) + "\\" else: r_str = "" line = l_str + r_str print(line)def right_wave(water_l, water_r): """When right side of wave is largest""" if water_l: l_str = " " * water_l + "/" factor_r = water_r * 2 - 2 else: l_str = " " factor_r = water_r * 2 - 2 r_str = " " * factor_r + "\\" line = l_str + r_str print(line)我調(diào)用的print_sequence()定義如下：def print_sequence(args): """Show all waves.""" for wave_height_l, wave_height_r in zip_longest(args[0::2], args[1::2], fillvalue=0): for water_l, water_r in zip_longest(reversed(range(1, wave_height_l + 1)), range(1, wave_height_r + 1), fillvalue=0): if wave_height_l > wave_height_r: left_wave(water_l, water_r) else: right_wave(water_l, water_r)運行如下：args = [11, 2, 5, 7, # 4 ]print_sequence(args)目前返回： /\ / \ / / / / / / / / / /\ / \ / \ / \ / \ \ \我現(xiàn)在正在努力解決的主要問題是：我在right_wave函數(shù)中犯的邏輯錯誤是什么？（縮進是錯誤的）。此外，我將如何開始在同一行上打印 2 個波浪？也許end=""在打印函數(shù)調(diào)用中用作參數(shù)？
2 回答
慕碼人2483693
TA貢獻1860條經(jīng)驗 獲得超9個贊
如果list是您的選擇，這里有一個打印波浪的簡單方法：
def print_wave(args):
total_cols = sum(args)
total_rows = args[0] # init total rows by first arg
matrix = [[' ' for _ in range(total_cols)] for _ in range(total_rows)]
curr_col = 0
curr_row = total_rows - 1
down = True
for num in args:
down = not down
char = '\\' if down else '/'
# update total rows and current row if need
if down:
diff = curr_row + num - total_rows
if diff > 0:
for _ in range(diff):
matrix.append([' ' for _ in range(total_cols)])
total_rows += diff
else:
diff = num - 1 - curr_row
if diff > 0:
for _ in range(diff):
matrix.insert(0, [' ' for _ in range(total_cols)])
total_rows += diff
curr_row += diff
for i in range(num):
matrix[curr_row][curr_col] = char
# for conjection not update curr row for the last loop
if i != num - 1:
if down:
curr_row += 1
else:
curr_row -= 1
curr_col += 1
for row in matrix:
for col in row:
print(col, end='')
print()
簡單測試args=[3, 5, 4, 11, 2, 5, 7]：
/\
/ \ /\
/ \ / \
\ / \
\/ \
\
\
\
\ /
\ /
\ /\ /
\/ \ /
\ /
\ /
\/
希望這會有所幫助。
呼如林
TA貢獻1798條經(jīng)驗 獲得超3個贊
當(dāng)它是 python 2x 時，這很簡單，它是由末尾的一個簡單逗號完成的魔術(shù)，例如。Print("a"), Print("b") 輸出：ab Incase of python 3x
你必須使用。end=" " 控制下一個打印函數(shù)之間的空格
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