我有簡單的 struct 和 reciver 我嘗試用 struct 設(shè)置映射然后調(diào)用 reciver 像這樣：package mainimport ( "fmt")type myStruct struct { FirstName string LastName string}func (m *myStruct) GetFirstName() string { return m.FirstName}func (m *myStruct) GetLastName() string { return m.LastName}func main() { testMyStruct := myStruct { FirstName: "x1", LastName: "x2", } myMapStruct["test2"] = testMyStruct fmt.Println(myMapStruct["test2"].GetFirstName())}我收到此錯(cuò)誤： cannot call pointer method getFirstName on myStruct為什么我可以從地圖調(diào)用 reciver 方法？
1 回答
慕哥9229398
TA貢獻(xiàn)1877條經(jīng)驗(yàn) 獲得超6個(gè)贊
當(dāng)你傳遞一個(gè)receiver指針時(shí)，你必須使用指向結(jié)構(gòu)的指針來調(diào)用它，請看下面的代碼
package main
import (
"fmt"
)
type myStruct struct {
FirstName string
LastName string
}
func (m *myStruct) GetFirstName() string {
return m.FirstName
}
func (m *myStruct) GetLastName() string {
return m.LastName
}
func main() {
testMyStruct := &myStruct {
FirstName: "x1",
LastName: "x2",
}
myMapStruct:=make(map[string]*myStruct)
myMapStruct["test2"] = testMyStruct
fmt.Println(myMapStruct["test2"].GetFirstName())
}
看到在這里工作
receiver或者如果作為值傳遞，您可以像下面這樣使用
package main
import (
"fmt"
)
type myStruct struct {
FirstName string
LastName string
}
func (m myStruct) GetFirstName() string {
return m.FirstName
}
func (m myStruct) GetLastName() string {
return m.LastName
}
func main() {
testMyStruct := myStruct {
FirstName: "x1",
LastName: "x2",
}
myMapStruct:=make(map[string]myStruct)
myMapStruct["test2"] = testMyStruct
fmt.Println(myMapStruct["test2"].GetFirstName())
}
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