我正在制作一個(gè)將數(shù)字轉(zhuǎn)換為文本的轉(zhuǎn)換器。我按照本網(wǎng)站中所說(shuō)的進(jìn)行了所有操作，并針對(duì)使用大整數(shù)進(jìn)行了編輯，但隨后顯示變量未初始化。我編輯了一些東西以使其與大整數(shù)兼容以獲得更大的數(shù)字，但它只是顯示變量 veryFar 可能未初始化。（我編輯了變量名來(lái)嘗試修復(fù)它?。?。package com.example.convertnumbertotext;import java.math.BigInteger;import java.text.DecimalFormat;public class EnglishNumberToWords {    private static BigInteger bi = new BigInteger("100");    private static BigInteger bi2 = new BigInteger("20");    private static BigInteger bi3 = new BigInteger("10");    private static final String[] tensNames = { "", " ten", " twenty", " thirty", " forty",            " fifty", " sixty", " seventy", " eighty", " ninety" };    private static final String[] numNames = { "", " one", " two", " three", " four", " five",            " six", " seven", " eight", " nine", " ten", " eleven", " twelve", " thirteen",            " fourteen", " fifteen", " sixteen", " seventeen", " eighteen", " nineteen" };    private static String convertLessThanOneThousand(BigInteger number) {        String veryFar;        BigInteger[] bii = number.divideAndRemainder(bi);        BigInteger[] bii2 = number.divideAndRemainder(bi3);        int resut = bii[1].compareTo(bi2);        if (resut == -1) {            veryFar = numNames[bii[1].intValue()];            number = number.divide(bi);        } else if (resut == 1 || resut == 0) {            veryFar = numNames[bii2[1].intValue()];            number = number.divide(bi3);            veryFar = tensNames[bii2[1].intValue()] + veryFar;            number = number.divide(bi3);        }        if (number.compareTo(BigInteger.valueOf(0)) == 0)            return veryFar;            return numNames[number.intValue()] + " hundred" + veryFar;    }}它顯示 2 條相同的錯(cuò)誤消息 - 錯(cuò)誤：變量 veryFar 可能尚未初始化 錯(cuò)誤：變量 veryFar 可能尚未初始化