是否有一個(gè)Iterable對(duì)象可以持有的鉤子/dunder，以便內(nèi)置filter函數(shù)可以擴(kuò)展到Iterable類（而不僅僅是實(shí)例）？當(dāng)然也可以自己寫(xiě)一個(gè)自定義filter_iter函數(shù)，比如：def filter_iter(filt_func: callable, collection_cls: type):    name = 'Filtered' + collection_cls.__name__  # would this automatic scheme lead to namespace conflicts?    wrapped_cls = type(name, (collection_cls,), {'_filt_func': staticmethod(filt_func)})    def __iter__(self):        yield from filter(self._filt_func, super(wrapped_cls, self).__iter__())    wrapped_cls.__iter__ = __iter__    return wrapped_cls這會(huì)產(chǎn)生預(yù)期的效果。例如，from collections import Collection, Iterableclass Chunker(Iterable):    def __init__(self, source: Iterable, chk_size: int=2):        self._source = source        self._chk_size = chk_size    def __iter__(self):        yield from zip(*([iter(self._source)] * self._chk_size))chunker = Chunker(range(12), 2)assert list(chunker) == [(0, 1), (2, 3), (4, 5), (6, 7), (8, 9), (10, 11)]FilteredChunker = filter_iter(lambda x: sum(x) % 3 == 0, Chunker)filtered_chunker = FilteredChunker(range(12))assert list(filtered_chunker) == [(4, 5), (10, 11)]但是，就像有一個(gè)__iter__鉤子可以確定如何迭代一個(gè)對(duì)象（例如，list在對(duì)象上調(diào)用時(shí)應(yīng)該如何表現(xiàn)），是否有一種__filter__鉤子可以確定filter在該對(duì)象上調(diào)用時(shí)應(yīng)該如何表現(xiàn)？如果不是，關(guān)于過(guò)濾可迭代對(duì)象的最佳實(shí)踐或標(biāo)準(zhǔn)是什么？