請(qǐng)問(wèn)有人可以幫我從我的元組列表中刪除多余的括號(hào)嗎？latest_Value = {"17:00:00": 100.00}Dict1 = {"current value": 100, "stock_purchased": "false", "Historic value": [('16:00:00', 55.50), ("15:00:00", 45.50), ("14:00:00", 75.50),("13:00:00", 65.50), ("12:00:00", 55.50)]}# converting the latest_value into a tupleList_it = [(k, v) for k, v in latest_Value.items()]# insert the tuple into the tuple listDict1['Historic value'].insert(0, List_it)data2 = Dict1["Historic value"]print(data2)#output [[('17:00:00', 100.0)], ('16:00:00', 55.5), ('15:00:00', 45.5), ('14:00:00', 75.5), ('13:00:00', 65.5), ('12:00:00', 55.5)]當(dāng)列表被修改時(shí)，它會(huì)添加一個(gè)嵌套列表而不僅僅是元組。你如何避免這種情況？
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長(zhǎng)風(fēng)秋雁
TA貢獻(xiàn)1757條經(jīng)驗(yàn) 獲得超7個(gè)贊
# converting the latest_value into a tuple List_it = [(k, v) for k, v in latest_Value.items()]
那實(shí)際上是錯(cuò)誤的。這會(huì)將整個(gè) dict 轉(zhuǎn)換為元組，而不僅僅是最后一個(gè)鍵值對(duì)，因此Dict1['Historic value'].insert(0, List_it)將整個(gè)元組列表添加到Dict1['Historic value'].
latest_Value包含單個(gè)鍵值對(duì)的事實(shí)不會(huì)改變將List_it是元組列表的事實(shí)。
如果您更改為，Dict1['Historic value'].insert(0, List_it[0])那么您將獲得所需的輸出。
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