在此處為我的練習(xí)表輸入圖像描述，我需要編寫(xiě)一個(gè)函數(shù)，該函數(shù)在沒(méi)有任何庫(kù)函數(shù)的情況下找到函數(shù)（稱(chēng)為 Maxwell_Boltzmann）的給定 y 值的 x 值。所以我嘗試定義函數(shù)（稱(chēng)為 most_probable_speed），它首先找到 Maxwell_Boltzmann 的 y 值的最大值，然后找到達(dá)到最大值的 x（在我的代碼中定義為 v）。我用for和if循環(huán)嘗試打印v，但它沒(méi)有打印出達(dá)到最大值的參數(shù)v，而是給了我整個(gè)向量v。有誰(shuí)知道我如何打印參數(shù)v，達(dá)到 y 了嗎？我的代碼是：import numpy as npimport matplotlib.pyplot as pltimport scipyimport scipy.constants as csv= np.linspace(-100,10000,1000) #this are my x values#this is my function, which prints y value in fonction of xdef Maxwell_Boltzmann(v, m, T):      ''' calculate the Maxwell-Boltzmann  distribution      for the speed of the chemical elements      3 parameters: -the speed of the particle              -its masse              -its temperature'''      y = np.sqrt(2/np.pi) * (m /( cs.k * T))**(3/2) * v**2 * np.exp(-m*v**2/(2 * cs.k * T))       return y;# this is the function which is suppose to find the x value given the y valuedef most_probable_speed(v,m,T):       '''determine the most probable speed of a given mass and temperature'''       x = Maxwell_Boltzmann(v, m, T) #put the y values of Maxwel_B for all x in an array named x       highest_probability = np.amax(x) #Return the maximum value of y       # I want to print the value of v for whcih Maxwell_Boltzmann(v, m, T)= highest_probability       for a in Maxwell_Boltzmann(v, m, T):           if a == highest_probability:               print(v)           else:               continuereturn highest_probability;m_oxy = 15.99 * cs.u most_probable_speed(v, m = m_oxy, T = 273)