我想捕獲 InputMissmatchException 但不停止重新執(zhí)行代碼（我希望 while 循環(huán)再次重新運(yùn)行，直到給出適當(dāng)?shù)妮斎耄┱麛?shù)選擇 = 0；布爾循環(huán)=真； while(loop){ printInstruction(); choice = scanner.nextInt(); //catch InputMissmatchException switch(choice){ case 0: loop = false; break; case 1: addCustomer(mohamad,sgbl); break; case 2: deleteCustomer(sgbl); break; case 3: seeInfo(sgbl); break; case 4: makeTransaction(mohamad); break; case 5: seeTransactionLog(mohamad); break; default: System.out.println("try again"); } }
1 回答
郎朗坤
TA貢獻(xiàn)1921條經(jīng)驗(yàn) 獲得超9個(gè)贊
int a = -1;
while(true)
{
try
{
Scanner in = new Scanner(System.in);
a = in.nextInt();
}
catch(InputMismatchException e)
{
e.printStackTrace();
}
//Your switch statement
}
順便說一下，a 的默認(rèn)值設(shè)置為 -1。如果發(fā)生異常，則進(jìn)入 switch case 時(shí)的值將是 -1。
int a = -1;
while(true)
{
try
{
Scanner in = new Scanner(System.in);
a = in.nextInt();
}
catch(InputMismatchException e)
{
e.printStackTrace();
continue;
}
//Your switch statement
}
如果您使用 continue 則循環(huán)的當(dāng)前迭代將停止并運(yùn)行下一次迭代
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