具有這種格式的文本文件有超過 50K 行M:org.apache.mahout.common.RandomUtilsTest:testHashDouble():['(O)java.lang.Double:<init>(double)', '(M)java.lang.Double:hashCode()', '(S)org.apache.mahout.common.RandomUtils:hashDouble(double)', '(S)org.apache.mahout.common.RandomUtilsTest:assertEquals(long,long)', '(O)java.lang.Double:<init>(double)']M:org.apache.mahout.common.RandomUtilsTest:testHashFloat():['(M)java.util.Random:nextLong()', '(M)java.util.Random:nextLong()', '(M)java.util.Random:nextLong()', '(S)org.apache.mahout.common.RandomUtilsTest:assertEquals(java.lang.String,long,long)']M:org.apache.mahout.math.AbstractVectorTest:testAssignBinaryFunction():['(I)org.apache.mahout.math.Vector:assign(org.apache.mahout.math.Vector,org.apache.mahout.math.function.DoubleDoubleFunction)', '(O)java.lang.StringBuilder:<init>()', '(I)org.apache.mahout.math.Vector:getQuick(int)', '(S)org.apache.mahout.math.AbstractVectorTest:assertEquals(java.lang.String,double,double,double)']M:org.apache.mahout.math.AbstractVectorTest:testAssignBinaryFunction2():['(S)org.apache.mahout.math.function.Functions:plus(double)', '(I)org.apache.mahout.math.Vector:assign(org.apache.mahout.math.function.DoubleFunction)', '(S)org.apache.mahout.math.AbstractVectorTest:assertEquals(java.lang.String,double,double,double)']如何讀取這些數(shù)據并將其格式化為字典，以便 [] 中的所有方法都是單獨的值，而 [ （測試方法）之前的字符串是鍵？在將它們作為值存儲在字典中之前，我將如何刪除它們？＃Python這是用于填充文本文件的代碼。現(xiàn)在我正在嘗試獲取該 txt 文件數(shù)據并將其讀/解析回另一個字典。 d = {} with open("filtered.txt") as input: for line in input: (key, val) = line.strip().split(" ") if str(key) in d: d[str(key)].append(val) else: d[str(key)] = [val] keys = [] for key in d: keys.append(key) keys.sort() input.close() with open('mahout-coverage.txt', 'w') as outfile: for key in keys: outfile.writelines('{}:{}'.format(key, d[key]) + "\n")
2 回答
aluckdog
TA貢獻1847條經驗 獲得超7個贊
json 模塊可用于將 python 字典存儲到文件中，然后加載文件并在將其寫入文件之前將其解析為相同的數(shù)據類型。
d = {}
with open('filtered.txt') as input:
for line in input:
key, value = line.strip().split("():")
key = "{}()".format(key)
d[key] = value
print(d)
# It would be better and easy if you write the data to the file using json module
import json
with open('data.txt', 'w') as json_file:
json.dump(d, json_file)
# Later you can read the file using the json module itself
with open('data.txt') as f:
# this data would be a dicitonay which can be easily managed.
data = json.load(f)
慕蓋茨4494581
TA貢獻1850條經驗 獲得超11個贊
使用ast.literal_eval您可以將字符串列表轉換為list
from collections import defaultdict
import ast
with open('tst.txt') as fp:
d = defaultdict(list)
for line in fp:
k, v = line[: line.index('):') + 1], ast.literal_eval(line[line.index(':[') + 1:])
d[k] += v
print(dict(d))
輸出：
{
M:org.apache.mahout.common.RandomUtilsTest:testHashDoubl : ['(O)java.lang.Double:<init>(double)', '(M)java.lang.Double:hashCode()', '(S)org.apache.mahout.common.RandomUtils:hashDouble(double)', '(S)org.apache.mahout.common.RandomUtilsTest:assertEquals(long,long)', '(O)java.lang.Double:<init>(double)']
M:org.apache.mahout.common.RandomUtilsTest:testHashFloa : ['(M)java.util.Random:nextLong()', '(M)java.util.Random:nextLong()', '(M)java.util.Random:nextLong()', '(S)org.apache.mahout.common.RandomUtilsTest:assertEquals(java.lang.String,long,long)']
M:org.apache.mahout.math.AbstractVectorTest:testAssignBinaryFunctio : ['(I)org.apache.mahout.math.Vector:assign(org.apache.mahout.math.Vector,org.apache.mahout.math.function.DoubleDoubleFunction)', '(O)java.lang.StringBuilder:<init>()', '(I)org.apache.mahout.math.Vector:getQuick(int)', '(S)org.apache.mahout.math.AbstractVectorTest:assertEquals(java.lang.String,double,double,double)']
M:org.apache.mahout.math.AbstractVectorTest:testAssignBinaryFunction : ['(S)org.apache.mahout.math.function.Functions:plus(double)', '(I)org.apache.mahout.math.Vector:assign(org.apache.mahout.math.function.DoubleFunction)', '(S)org.apache.mahout.math.AbstractVectorTest:assertEquals(java.lang.String,double,double,double)']
}
添加回答
舉報
0/150
提交
取消