我有一個(gè)添加新用戶帳戶的 php 腳本。addAccount() 的一部分檢查用戶名是否有效，如果無效，則返回不可用的異常（出現(xiàn)致命錯(cuò)誤）。我的問題是 AJAX 將一切都解釋為成功并無論如何都顯示成功消息。如何解決此問題或至少捕獲致命錯(cuò)誤并顯示正確的消息？$(document).on('click', '#createUserBtn', function(e){ e.preventDefault(); $.ajax({ url:'addUser.php', type:'post', data:$('#addUser').serialize(), success:function(){ toastr.success("User successfully added!"); }, error: function(){ toastr.warning('Uh-oh! Something went wrong with adding this user!'); } });});添加用戶.php<?phpsession_start();/* Include the database connection file (remember to change the connection parameters) */require './db_inc.php';/* Include the Account class file */require './account_class.php'; $type = $_POST['type']; $username = $_POST['uname']; $password = $_POST['password']; $comp = $_POST['company']; $email = $_POST['email']; $fname = $_POST['fname']; $lname = $_POST['lname']; $query = $pdo->query("SELECT * FROM accounts WHERE email ='".$email."'");$account = new Account();// Will print all the values received. $newId = $account->addAccount($username, $password, $comp, $email, $fname, $lname, $type); header('Location: ./dashboard.php?user='.$username);?>這是使用的 addAccount 函數(shù)... public function addAccount(string $name, string $passwd, string $comp, string $email, string $fname, string $lname, string $type): int { /* Global $pdo object */ global $pdo; /* Trim the strings to remove extra spaces */ $name = trim($name); $passwd = trim($passwd); /* Check if the user name is valid. If not, throw an exception */ if (!$this->isNameValid($name)) { throw new Exception('Invalid user name'); } /* Check if the password is valid. If not, throw an exception */ if (!$this->isPasswdValid($passwd)) { throw new Exception('Invalid password'); }
2 回答
MYYA
TA貢獻(xiàn)1868條經(jīng)驗(yàn) 獲得超4個(gè)贊
首先，如果您從 javascript 請求某些內(nèi)容，則無法通過 php 重定向用戶，請從 addUser.php 中刪除此行
header('Location: ./dashboard.php?user='.$username);
現(xiàn)在要將結(jié)果從 php 返回到客戶端，您必須DIE使用帶有值的 php，最好的方法是 JSON
在 addUser.php 檢查你想要什么并返回如下值：
<?php
session_start();
/* Include the database connection file (remember to change the connection parameters) */
require './db_inc.php';
/* Include the Account class file */
require './account_class.php';
$type = $_POST['type'];
$username = $_POST['uname'];
$password = $_POST['password'];
$comp = $_POST['company'];
$email = $_POST['email'];
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$query = $pdo->query("SELECT * FROM accounts WHERE email ='".$email."'");
$account = new Account();
// Will print all the values received.
$newId = $account->addAccount($username, $password, $comp, $email, $fname, $lname, $type);
if(intval($newId) > 0) // if user created
die(json_encode(array('status' => 'ok')));
else
die(json_encode(array('status' => 'error')));
?>
然后更改您的客戶端，如下所示：
$(document).on('click', '#createUserBtn', function(e){
e.preventDefault();
$.ajax({
url:'addUser.php',
type:'post',
data:$('#addUser').serialize(),
dataType: "json", // <- Add this line
success:function(response){ // <- add response parameter
//Here check result
if(response['status'] == 'ok')
toastr.success("User successfully added!");
else
toastr.warning('Uh-oh! Something went wrong with adding this user!');
},
error: function(){
},
statusCode: { // <- Add this property
500: function() {
toastr.warning('Uh-oh! Something went wrong with adding this user!');
}
}
});
});
慕桂英546537
TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超10個(gè)贊
您可以使用http_response_code()返回 HTTP 錯(cuò)誤代碼（通常代碼 500 ：內(nèi)部服務(wù)器錯(cuò)誤）。
您可以使用 try/catch 塊來做到這一點(diǎn)：
try
{
...
$account = new Account();
// Will print all the values received.
$newId = $account->addAccount($username, $password, $comp, $email, $fname, $lname, $type);
header('Location: ./dashboard.php?user='.$username);
}
catch(Exception $e)
{
http_response_code(500);
exit();
}
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