我正在嘗試從 Web 服務(wù)獲取令牌，并且正在使用 Spring Boot 進(jìn)行編碼，但是當(dāng)我運(yùn)行應(yīng)用程序時(shí)，我收到以下錯(cuò)誤消息：“嘗試序列化 java.lang.Class: org.springframework.beans .factory.annotation.Qualifier。忘記注冊(cè)類型適配器？”。我查看了具有相同問(wèn)題的不同在線帖子，但我不明白我做錯(cuò)了什么。我調(diào)試到出現(xiàn)錯(cuò)誤并且 tokenRequest 包含調(diào)用的所有信息package com.ids.app;import org.springframework.beans.factory.annotation.Autowired;import org.springframework.boot.CommandLineRunner;import org.springframework.boot.SpringApplication;import org.springframework.boot.autoconfigure.SpringBootApplication;import com.ids.app.controller.FE_ControlController;@SpringBootApplication(scanBasePackages={"io.swagger.client","com.ids.app.controller","com.ids.app.service"})public class IdsFeApplication implements CommandLineRunner{ @Autowired private FE_ControlController fec; public static void main(String[] args) { SpringApplication.run(IdsFeApplication.class, args); } @Override public void run(String... args) throws Exception { System.out.println("Hello world!!!"); fec.selWebServiceAndUsernameAndPassword("A"); }}package com.ids.app.controller;import java.util.List;import org.springframework.beans.factory.annotation.Autowired;import org.springframework.context.annotation.ComponentScan;import org.springframework.stereotype.Controller;import com.ids.app.entities.FE_Control;import com.ids.app.service.FE_ControlService;import io.swagger.client.ApiClient;import io.swagger.client.ApiException;import io.swagger.client.api.AuthorizationApi;import io.swagger.client.model.TokenRequest;import io.swagger.client.model.TokenResponse;@Controller@ComponentScanpublic class FE_ControlController { @Autowired private FE_ControlService fe; @Autowired private ApiClient api; @Autowired private AuthorizationApi authorizationApi; @Autowired private TokenRequest tokenRequest }}
2 回答
撒科打諢
TA貢獻(xiàn)1934條經(jīng)驗(yàn) 獲得超2個(gè)贊
這里TokenRequest是一個(gè) Spring-bean，它不是一個(gè)簡(jiǎn)單的 java 對(duì)象，而是一個(gè)具有 spring 特定屬性的代理。因此，當(dāng)您調(diào)用authorizationApi.token(tokenRequest)它時(shí)，它會(huì)嘗試序列化對(duì)象并失敗，因?yàn)樗鼰o(wú)法序列化特定于 bean 的類（在您的情況下Qualifier）。
TokenRequest 不應(yīng)該是 spring 管理的 bean，而是一個(gè)簡(jiǎn)單的 java 對(duì)象。因此，刪除自動(dòng)裝配并使其成為方法變量實(shí)例，而不是保持在類級(jí)別。
TokenRequest tokenRequest = new TokenRequest(); tokenRequest.setGrantType(TokenRequest.GrantTypeEnum.PASSWORD); tokenRequest.setUsername(username); tokenRequest.setPassword(password); tokenResponse=authorizationApi.token(tokenRequest); accessToken = tokenResponse.getAccessToken();
子衿沉夜
TA貢獻(xiàn)1828條經(jīng)驗(yàn) 獲得超3個(gè)贊
嘗試使用以下代碼通過(guò) POST 請(qǐng)求從 Web 服務(wù)獲取令牌。它會(huì)起作用的。
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.URL;
public void getHttpCon() throws Exception {
String POST_PARAMS = "grant_type=password&username=someusrname&password=somepswd&scope=profile";
URL obj = new URL("http://someIP/oauth/token");
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "application/json;odata=verbose");
con.setRequestProperty("Authorization",
"Basic Base64_encoded_clientId:clientSecret");
con.setRequestProperty("Accept",
"application/x-www-form-urlencoded");
// For POST only - START
con.setDoOutput(true);
OutputStream os = con.getOutputStream();
os.write(POST_PARAMS.getBytes());
os.flush();
os.close();
// For POST only - END
int responseCode = con.getResponseCode();
System.out.println("POST Response Code :: " + responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) { //success
BufferedReader in = new BufferedReader(new InputStreamReader(
con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// print result
System.out.println(response.toString());
} else {
System.out.println("POST request not worked");
}
}
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