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Python從列表中刪除特定項(xiàng)目

Python從列表中刪除特定項(xiàng)目

泛舟湖上清波郎朗 2022-10-25 14:57:03
這是我的列表代碼:saptamani = []for months in range(1, 12):    luna = calendar.monthcalendar(2020, months)    saptamani.append(luna)    sapt_l = []print(saptamani)這是此列表的輸出:[[[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 31, 0, 0]], [[0, 0, 0, 0, 0, 1, 2], [3, 4, 5, 6, 7, 8, 9], [10, 11, 12, 13, 14, 15, 16], [17, 18, 19, 20, 21, 22, 23], [24, 25, 26, 27, 28, 29, 0]], [[0, 0, 0, 0, 0, 0, 1], [2, 3, 4, 5, 6, 7, 8], [9, 10, 11, 12, 13, 14, 15], [16, 17, 18, 19, 20, 21, 22], [23, 24, 25, 26, 27, 28, 29], [30, 31, 0, 0, 0, 0, 0]], [[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 0, 0, 0]], [[0, 0, 0, 0, 1, 2, 3], [4, 5, 6, 7, 8, 9, 10], [11, 12, 13, 14, 15, 16, 17], [18, 19, 20, 21, 22, 23, 24], [25, 26, 27, 28, 29, 30, 31]], [[1, 2, 3, 4, 5, 6, 7], [8, 9, 10, 11, 12, 13, 14], [15, 16, 17, 18, 19, 20, 21], [22, 23, 24, 25, 26, 27, 28], [29, 30, 0, 0, 0, 0, 0]], [[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 31, 0, 0]], [[0, 0, 0, 0, 0, 1, 2], [3, 4, 5, 6, 7, 8, 9], [10, 11, 12, 13, 14, 15,16], [17, 18, 19, 20, 21, 22, 23], [24, 25, 26, 27, 28, 29, 30], [31, 0, 0, 0, 0, 0, 0]], [[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13], [14, 15, 16, 17, 18, 19, 20], [21, 22, 23, 24, 25, 26, 27], [28, 29, 30, 0, 0, 0, 0]], [[0, 0, 0, 1, 2, 3, 4], [5, 6, 7, 8, 9, 10, 11], [12, 13, 14, 15, 16, 17, 18], [19, 20, 21, 22, 23, 24, 25], [26, 27, 28, 29, 30, 31, 0]], [[0, 0, 0, 0, 0, 0, 1], [2, 3, 4, 5, 6, 7, 8], [9, 10, 11,12, 13, 14, 15], [16, 17, 18, 19, 20, 21, 22], [23, 24, 25, 26, 27, 28, 29], [30, 0, 0, 0, 0, 0, 0]]]我該如何做才能只保留大于 0 的項(xiàng)目,例如在這種情況下:[0, 0, 1, 2, 3, 4, 5]成為:[1, 2, 3, 4, 5]
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2 回答

?
四季花海

TA貢獻(xiàn)1811條經(jīng)驗(yàn) 獲得超5個(gè)贊

只需在附加之前添加一個(gè) if 語句:


saptamani = []

for months in range(1, 12):

    luna = [m for m in calendar.monthcalendar(2020, months) if m > 0]

    saptamani.append(luna)


print(saptamani)

或者 - 作為列表理解:


saptamani = [luna 

             for months in range(1, 12) 

             for luna in [m for m in calendar.monthcalendar(2020, months) if m > 0]]



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?
ITMISS

TA貢獻(xiàn)1871條經(jīng)驗(yàn) 獲得超8個(gè)贊

saptamani = []

for months in range(1, 12):

    luna = calendar.monthcalendar(2020, months)

    for i in luna:

        prepare = [m for m in i if m > 0]

        saptamani.append(new_w)


print(saptamani)

@Jan,你的回答幫助了我。這就是它的工作原理


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