我正在嘗試旋轉(zhuǎn)（對齊）圖像，其中P1包含P2沿y-axis原圖：注：綠色區(qū)域代表原圖結(jié)果應(yīng)該是：注：紅色區(qū)域代表旋轉(zhuǎn)后的原圖所以我需要計算由P1(x1,y1)andP2(x2,y2)和 by定義的線之間的角度y-axis，我的代碼是：import cv2import numpy as npfrom math import *import mathimport imutilsheight = 500width = 500original_image = np.zeros((height,width,3), np.uint8)original_image[:] = (0,255,0)x1 = 400y1 = 50P1 = (x1, y1)x2 = 100y2 = 300P2 = (x2, y2)cv2.line(original_image, P1, P2, (0, 0, 0), 3)deltaY = y1 - y2deltaX = x1 - x2angleInDegrees = atan2(deltaY, deltaX) * 180 / math.piprint(angleInDegrees)rotated_image = imutils.rotate_bound(original_image, angleInDegrees)cv2.imshow("Original", original_image)cv2.imshow("Rotated", rotated_image)cv2.waitKey(0)但是我的rotated_image 沒有正確對齊結(jié)果如下：我應(yīng)該如何解決它？
1 回答
POPMUISE
TA貢獻(xiàn)1765條經(jīng)驗 獲得超5個贊
首先，您正在計算錯誤的角度。您正在計算的角度介于起源于原點并結(jié)束于 P1 的向量與起源于原點并結(jié)束于 P2 的向量之間。
您需要的角度介于從 P1 開始到 P2 結(jié)束[P2-P1]的向量與表示 y 軸方向的向量之間，即[0, 1].
其次，您必須考慮到您的原點位于左上角，因此您需要在計算后反映角度。
import cv2
import numpy as np
from math import *
import math
import imutils
height = 500
width = 500
original_image = np.zeros((height,width,3), np.uint8)
original_image[:] = (0,255,0)
x1 = 400
y1 = 50
P1 = np.array([x1, y1])
x2 = 100
y2 = 300
P2 = np.array([x2, y2])
# checks orientation of p vector & selects appropriate y_axis_vector
if (P2[1] - P1[1]) < 0:
y_axis_vector = np.array([0, -1])
else:
y_axis_vector = np.array([0, 1])
if (P2[0] - P1[0]) < 0 and (P2[1] - P1[1]) :
y_axis_vector = np.array([0, 1])
p_unit_vector = (P2 - P1) / np.linalg.norm(P2-P1)
angle_p_y = np.arccos(np.dot(p_unit_vector, y_axis_vector)) * 180 /math.pi
cv2.line(original_image, tuple(P1), tuple(P2), (0, 0, 0), 3)
print(angle_p_y)
print (P2-P1)
rotated_image = imutils.rotate_bound(original_image, -angle_p_y)
cv2.imshow("Original", original_image)
cv2.imshow("Rotated", rotated_image)
cv2.waitKey(0)
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