對于structs，可以定義一個func可以更新struct變量的 a。有什么方法可以使用這些功能interface嗎？在以下代碼中，我嘗試創(chuàng)建一個最小示例來描述我的問題。和中struct的兩個被定義。兩者都有和功能。 函數(shù)計算形狀的周長。函數(shù)通過改變其屬性來增加形狀的周長。還定義了與方法簽名的接口。RectCirclestructPerimeterExpandPerimeterExpandShapePerimeterviewShapeData函數(shù)接受Shape類型的輸入?yún)?shù)。此函數(shù)查看形狀的數(shù)據(jù)并運(yùn)行該P(yáng)erimeter方法并查看形狀的周長。package mainimport "fmt"type Shape interface {    Perimeter() float64}type Rect struct {    width  float64    height float64}type Circle struct {    radius float64}func (s Rect) Perimeter() float64 {    return 2 * (s.width + s.height)}func (s Circle) Perimeter() float64 {    return 2 * 3.14 * s.radius}func (s *Rect) Expand(increaseValue float64) {    s.width += increaseValue / 2}func (s *Circle) Expand(increaseValue float64) {    s.radius += increaseValue / 3.14 / 2}func main() {    a := Circle{radius: 10.0}    b := Rect{width: 2.4, height: 5}    a.Expand(1)    viewShapeData(a)    b.Expand(1)    viewShapeData(b)}func viewShapeData(s Shape) {    fmt.Printf("value: %v, Type: %T, Perimeter: %f\n", s, s, s.Perimeter())}現(xiàn)在我正在尋找Expand一種在函數(shù)中調(diào)用方法的方法viewShapeData。我嘗試了不同的方法并在描述的代碼中應(yīng)用了以下更改：type Shape interface {    Perimeter() float64    Expand(float64)}func main() {    a := Circle{radius: 10.0}    b := Rect{width: 2.4, height: 5}    viewShapeData(a)    viewShapeData(b)}func viewShapeData(s Shape) {    s.Expand(1)    fmt.Printf("value: %v, Type: %T, Perimeter: %f\n", s, s, s.Perimeter())}但是出現(xiàn)了這些錯誤：cannot use a (type Circle) as type Shape in argument to viewShapeData:        Circle does not implement Shape (Expand method has pointer receiver)cannot use b (type Rect) as type Shape in argument to viewShapeData:        Rect does not implement Shape (Expand method has pointer receiver)請給我一個解決方案或告訴我為什么 Golang 不支持這種編碼。