我有兩個(gè)關(guān)于while循環(huán)的問(wèn)題！我不想浪費(fèi)你的時(shí)間，但我真的需要幫助。1，在我的代碼中，while true: 還有一個(gè) while 存在。我知道我可以打破第二個(gè)while循環(huán)，但我怎樣才能同時(shí)打破第一個(gè)while循環(huán)？2，在代碼“if stand_hit == 'h'; 的末尾有沒(méi)有回到stand_hit == 's'？我不希望它在通過(guò)stand_hit == h 后顯示打?。╩ycard）的東西。我愿意想拿起新卡或立即站立。謝謝！如果您對(duì)我的問(wèn)題沒(méi)有意義，請(qǐng)發(fā)表評(píng)論！while True:player_card = []player_card.append(player_draw())player_card.append(player_draw())print('your cards:',player_card[0]+player_color,player_card[1]+player_color)player_total = card_dict[player_card[0]]+card_dict[player_card[1]] dealer_card = []dealer_card.append(dealer_draw())dealer_card.append(dealer_draw())dealer_cards = []for i in dealer_card: dealer_cards.append(card_dict[i])dealer_total = sum(dealer_cards) player_card = []stand_hit = input('(S)tand or (H)it?...: ') if stand_hit == 's': print('Dealer cards:', dealer_card[0]+dealer_color, dealer_card[1]+dealer_color) while dealer_total < 17: if dealer_total < 11: card_dict['A'] = 11 elif dealer_total > 10: card_dict['A'] = 1 a = random.choice(list(card_dict)) print('Dealer drew:', a + dealer_color) dealer_total += card_dict[a] if dealer_total > 21: print('You win!') player_score += 1 print('Dealer:', dealer_score, 'Player:', player_score) play_again = input('Play again (Y/N)?...: ') if play_again == 'y': print() continue elif play_again == 'n': print('\n') print('>_') break
1 回答
蝴蝶不菲
TA貢獻(xiàn)1810條經(jīng)驗(yàn) 獲得超4個(gè)贊
根據(jù)內(nèi)循環(huán)中滿足的條件，我可以想到兩種方法來(lái)停止外循環(huán)。
偽代碼：
bln = True
while bln:
# Do stuff
while x < y:
if z == n:
# Break inner loop, and set bln to False to break outer loop
bln = False
break
第二種方法：
while True:
bln = False
# Do stuff
while x < y:
if z == n:
# Break inner loop, and set bln to True for later break statement
bln = True
break
if bln:
break
請(qǐng)注意，使用第一種方法，外部循環(huán)的迭代將完成，即使bln設(shè)置為 True。然而，第二種方法會(huì)突然中斷外循環(huán)。
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