這段代碼：$url = ('example.url');function Feed($url) { $feed = simplexml_load_file($url) or die('Cannot Connect'); $result = array(); foreach ($feed->channel->item as $content) { array_push($result, $content); } return $result;}飼料.php ^^require_once 'feed.php'; $title = '123'; foreach(Feed('example.url') as $f ) { if (strpos($f->title, $title) !== false) echo $f->children('georss', true)->children('gml', true)->children('gml', true). "<br>"; }輸出：59.838314 6.86571759.662615 10.56911059.709940 10.690916如何檢查數(shù)字是否在我指定的數(shù)字之間？例子：59.68000和之間的經(jīng)度59.850005.510000和之間的緯度8.750000它會(huì)輸出59.838314 6.865717編輯：顯示如果嘗試過： foreach(Feed('example') as $f ) { if (strpos($f->title, $title) !== false) if ($f->children('georss', true)->children('gml', true)->children('gml', true) >= 59.68000 && $f->children('georss', true)->children('gml', true)->children('gml', true) <= 59.85000) { echo $f->children('georss', true)->children('gml', true)->children('gml', true). "<br>"; } }在這里，我只檢查經(jīng)度。我想檢查兩者。任何幫助是極大的贊賞！
2 回答
倚天杖
TA貢獻(xiàn)1828條經(jīng)驗(yàn) 獲得超3個(gè)贊
在 PHP 中比較浮點(diǎn)值可能會(huì)有問題。如果這是您所要求的，您可以使用 bccomp() 來比較浮點(diǎn)值。
$a = '59.68000';
$b = '59.85000';
echo between($a, $b, '59.68001') . "\n"; // in range
echo between($a, $b, '59.68000') . "\n"; // exact match
echo between($a, $b, '59.88000') . "\n"; // higher than range
echo between($a, $b, '59.67000') . "\n"; // lower than range
function between($lower, $upper, $value)
{
// Value is greater than lower bound of range
$check1 = bccomp($value, $lower, 6) >= 0;
// Value is less than upper bounds of range
$check2 = bccomp($upper, $value, 6) >= 0;
if ( $check1 && $check2 ) {
return true;
}
return false;
}
使用功能：
foreach(Feed('https://www.vegvesen.no/trafikk/xml/savedsearch.rss?id=601') as $f ) {
if (strpos($f->title, $title) !== false) {
$long = $f->children('georss', true)->children('gml', true)->children('gml', true);
$lat = $f->lattitude_value(); // Replace me!!
if ( between('59.68000', '59.85000', $long) && between('5.510000', '8.750000', $lat) ) {
echo $long . ' ' . $lat . "<br>";
}
}
}
catspeake
TA貢獻(xiàn)1111條經(jīng)驗(yàn) 獲得超0個(gè)贊
我到處玩，發(fā)現(xiàn)這是解決我的問題的最佳方法：
foreach(Feed($url) as $f ) {
if (strpos($f->title, $title) !== false){
$pos = $f->children('georss', true)->children('gml', true)->children('gml', true);
list($number1, $number2) = explode(' ', $pos);
if ($number1 > 50.00000 && $number1 < 71.00000){
if ($number2 > 4.510000 && $number2 < 10.750000){
echo $f->children('georss', true)->children('gml', true)->children('gml', true). "<br>";
}
}
}
}
- 2 回答
- 0 關(guān)注
- 145 瀏覽
添加回答
舉報(bào)
0/150
提交
取消