2 回答
TA貢獻(xiàn)1802條經(jīng)驗(yàn) 獲得超5個(gè)贊
你可以簡(jiǎn)單地通過(guò)noWeekends: true。
$( ".add_delivery_date").datepicker( {
noWeekends: true,
minDate: 0,
firstDay: 0,
beforeShowDay: setHolidays
} );
TA貢獻(xiàn)1834條經(jīng)驗(yàn) 獲得超8個(gè)贊
這比我想象的要容易:
function setHolidays(date) {
for (i = 0; i < holidays.length; i++) {
if (date.getFullYear() == holidays[i][0]
&& date.getMonth() == holidays[i][1] - 1
&& date.getDate() == holidays[i][2]) {
return [false, 'holiday', holidays[i][3]];
}
}
var noWeekend = $.datepicker.noWeekends(date);
return !noWeekend[0] ? noWeekend : [true];
}
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