我正在嘗試根據(jù)人的身高生成尺寸。目前我的程序可以工作，但我想找到一種更短的方法來獲取大小，而不是使用所有這些else if語句。我想循環(huán)通過“斷點”來找到相應的索引。這是我的原始代碼+我的想法。const sizes = ['xxs', 'xxs or xs', 'xs', 'xs or s'] // Goes on for all sizes...function generateSize(height) {    let size;    if (height < 142) {        size = sizes[0];    } else if (height >= 142 && height < 148) {        size = sizes[1];    } else if (height >= 148 && height < 154) {        size = sizes[2];    } else if (height >= 154 && height < 160) {        size = sizes[3]; // Goes on for all sizes...    } else {        size = 'larger...';    }    return size;}// Example of what I had in mind.const heightBreakpoints = [142, 148, 154, 160];function getByBreakpoints(breakpoints, height){ // Part where I am stuck.    let index;    // Loop through breakpoints...    return index;}const sizeIndex = (getByBreakpoints(heightBreakpoints, 158));const s = sizes[sizeIndex];