我正在嘗試生成一個以遞歸方式填充的列表，該列表從方法變量中獲取輸入。（我相信）我的代碼：class Register: cur_unit = [100, 50, 20, 10, 5, 1, .25, .10, .05, .01] reg_amount = [] def load_reg(self): self.reg_amount = float(input('Enter amount of money in register...\n')) def transaction(self): trans_amount = float(input('Enter the cost of the transaction...\n')) if trans_amount > self.reg_amount: print("I'm sorry, but we don't have enough money in the register to allow this transaction...\n") else: cash_paid = float(input('Enter how much money you will pay with...\n')) change_due = cash_paid - trans_amount new_reg_amount = self.reg_amount - change_due if new_reg_amount < 0: print("I'm sorry, but we don't have enough money in the register to allow this transaction...\n") else: new_reg_amount = round(new_reg_amount, 2) change_due = round(change_due, 2) print('\n' + str(new_reg_amount)) print(change_due) for i in self.cur_unit: if change_due - i >= 0: return [i] + [cash_paid - i]reg = Register()reg.load_reg()res = reg.transaction()print(res)產(chǎn)生不良結(jié)果的結(jié)果：Enter amount of money in register...200Enter the cost of the transaction...24.24Enter how much money you will pay with...50174.2425.76[20, 30.0] # undesired resultProcess finished with exit code 0期望的結(jié)果，它將貫穿cur_unit，如果可以從cash_paid中減去單位而不change_due等于或小于0，則每個單位都會返回：（這是為了需要更多細節(jié)）[20, 5, .25, .25, .25, .01]
1 回答
慕姐4208626
TA貢獻1852條經(jīng)驗 獲得超7個贊
正如Prune在評論中指出的那樣，通過迭代比使用遞歸更好地解決了這個問題。我寫了一些方法，以防萬一你好奇：是一個遞歸函數(shù)，是一個更干凈的迭代解決方案。請注意，他們假設(shè)您的列表已排序。split_change_rsplit_changecur_unit
class Register:
cur_unit = [100, 50, 20, 10, 5, 1, .25, .10, .05, .01]
reg_amount = []
def load_reg(self):
self.reg_amount = float(input('Enter amount of money in register...\n'))
def split_change_r(self, amount, l = []):
next_cur = [a for a in self.cur_unit if a <= amount][0]
if next_cur == amount:
return l + [next_cur]
else:
# here is the recursive call
return self.split_change_r(round(amount - next_cur, 2), l + [next_cur])
def split_change(self, amount):
r = []
while(amount != 0):
next_cur = [a for a in self.cur_unit if a <= amount][0]
amount = round(amount - next_cur, 2)
r.append(next_cur)
return r
def transaction(self):
trans_amount = float(input('Enter the cost of the transaction...\n'))
if trans_amount > self.reg_amount:
print("I'm sorry, but we don't have enough money in the register to allow this transaction...\n")
else:
cash_paid = float(input('Enter how much money you will pay with...\n'))
change_due = cash_paid - trans_amount
new_reg_amount = self.reg_amount - change_due
if new_reg_amount < 0:
print("I'm sorry, but we don't have enough money in the register to allow this transaction...\n")
else:
new_reg_amount = round(new_reg_amount, 2)
change_due = round(change_due, 2)
print('\n' + str(new_reg_amount))
print(change_due)
return self.split_change(change_due)
reg = Register()
reg.load_reg()
res = reg.transaction()
print(res)
輸出示例：
Enter amount of money in register...
200
Enter the cost of the transaction...
24.24
Enter how much money you will pay with...
50
174.24
25.76
[20, 5, 0.25, 0.25, 0.25, 0.01]
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