我在洗牌兩副牌時遇到問題。我使用二維數(shù)組創(chuàng)建了兩個套牌。請記住，這些是要求。我還需要使用一種名為shuffle（）的方法對它們進行洗牌，該方法接收1D數(shù)組并返回1D數(shù)組。在洗牌兩副牌后，我需要從第一副牌中挑選前兩張牌，從第二副牌中挑選前兩張牌，并檢查它們是否匹配。以及獲得結(jié)果所需的洗牌次數(shù)。示例輸出：第1副牌中的兩張完全匹配卡牌是：鉆石王牌，俱樂部2張第2副牌中的兩張完全匹配卡牌是：鉆石王牌，俱樂部2張洗牌次數(shù)： 387這是我們參與的項目的第二部分，下面是我試圖解決這個問題的內(nèi)容。我嘗試使用下面的代碼創(chuàng)建套牌，這有效int[][] deck = new int[2][52];for (int i = 0; i <= deck.length - 1; i++) { for (int j = 0; j < deck[i].length; j++) { deck[i][j] = j; }}我寫了洗牌方法，但它似乎不起作用。public static int[] shuffle(int[] deck) { for(int i=0; i<deck.length; i++) { int index = (int)(Math.random()* deck.length); int temp = deck[i]; deck[i] = deck[index]; deck[index] = temp; }return deck; }下面的代碼是本項目第一部分的原始代碼，在對它進行洗牌并計算獲得四個這樣的代碼之后，我們需要從一個甲板上打印四個這樣的代碼。class Main { public static void main(String[] args) { String[] suit = { "Spades", "Hearts", "Diamond", "Clubs" }; String[] rank = { "Ace", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" }; int rank1, rank2, rank3, rank4, suit1, suit2, suit3, suit4, count = 0; int[] deck = new int[52]; for (int i = 0; i < deck.length; i++) { deck[i] = i; } do { count++; for (int i = 0; i < deck.length; i++) { int index = (int) (Math.random() * deck.length); int temp = deck[i]; deck[i] = deck[index]; deck[index] = temp; } suit1 = deck[0] / 13; suit2 = deck[1] / 13; suit3 = deck[2] / 13; suit4 = deck[3] / 13; rank1 = deck[0] % 13; rank2 = deck[1] % 13; rank3 = deck[2] % 13; rank4 = deck[3] % 13; } while (rank1 != rank2 || rank2 != rank3 || rank3 != rank4); System.out.println(" Four-of-kind cards: " + suit[suit1] + " of " + rank[rank1] + ", " + suit[suit2] + " of " + rank[rank2] + ", " + suit[suit3] + " of " + rank[rank3] + ", " + suit[suit4] + " of " + rank[rank4] + "\n Number of shuffled times: " + count); }}結(jié)果應(yīng)該再次如下所示。示例輸出：來自卡組1的兩張精確匹配卡是：鉆石王牌，俱樂部2卡組2中的兩張精確匹配卡牌是：鉆石王牌，俱樂部2洗牌次數(shù)： 387
1 回答
精慕HU
TA貢獻1845條經(jīng)驗 獲得超8個贊
您的方法是正確的。無需執(zhí)行另一個將接受 2D 數(shù)組的 shuffle 方法。您只需要在2D陣列的每個套牌中調(diào)用該方法即可。要做到這一點，只需：shuffleshuffle
deck[0] = shuffle(deck[0]);
deck[1] = shuffle(deck[1]);
我還更新了您的代碼，以便在出現(xiàn)其他要求時可以更輕松地進行修改。請參考以下代碼：
public class Main {
public static String[] card; // The holder for all cards
public static void main(String[] args) {
card = generateCardSuits(); // generate the cards with their corresponding suits
doPartOne();
doPartTwo();
}
/**
* Part One
*
*/
public static void doPartOne() {
System.out.println("========== PART ONE ==========");
int[] deck = generateAndShuffleInitialDeck();
int ctr = 1;
while (true) {
if (deck[0] % 13 == deck[1] % 13 && deck[1] % 13 == deck[2] % 13 && deck[2] % 13 == deck[3] % 13) {
break;
}
deck = shuffle(deck);
ctr++;
}
System.out.println("Four-of-kind cards are: " + card[deck[0]] + " , " + card[deck[1]] + " , " + card[deck[2]]
+ " and " + card[deck[3]]);
System.out.println("Number of shuffled times: " + ctr);
System.out.println("==============================");
}
/**
* Part Two
*
*/
public static void doPartTwo() {
System.out.println("========== PART TWO ==========");
int[][] deck = new int[2][52];
deck[0] = generateAndShuffleInitialDeck();
deck[1] = generateAndShuffleInitialDeck();
int ctr = 1;
while (deck[0][0] != deck[1][0] || deck[0][1] != deck[1][1]) {
deck[0] = shuffle(deck[0]);
deck[1] = shuffle(deck[1]);
ctr++;
}
System.out.println("Two exact match cards from deck 1 are: " + card[deck[0][0]] + " and " + card[deck[0][1]]);
System.out.println("Number of shuffled times: " + ctr);
System.out.println("==============================");
}
/**
* Generate an initial deck of cards and shuffle them
*
* @return The initial and shuffled deck of cards
*/
public static int[] generateAndShuffleInitialDeck() {
int[] deck = new int[52];
for (int j = 0; j < deck.length; j++) {
deck[j] = j;
}
return shuffle(deck);
}
/**
* Generate the cards with their corresponding suits
*
* @return The deck that will serve as the mapper for the cards to their suits
*/
public static String[] generateCardSuits() {
String[] rank = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" };
String[] suit = { "Spades", "Hearts", "Diamond", "Clubs" };
String[] cards = new String[52];
for (int i = 0, j = 0, s = 0; i < cards.length; i++) {
cards[i] = rank[j] + " of " + suit[s];
j++;
if (j == 13) { // Since each suit consist of 13 cards
j = 0;
s++;
}
}
return cards;
}
/**
* Shuffle the deck of cards
*
* @param deck
* the deck of cards to be shuffle
*
* @return The shuffled deck of cards
*/
public static int[] shuffle(int[] deck) {
for (int i = 0; i < deck.length; i++) {
int index = (int) (Math.random() * deck.length);
int temp = deck[i];
deck[i] = deck[index];
deck[index] = temp;
}
return deck;
}
}
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