我已經(jīng)成功地做了一個(gè)同步解決方案，沒有對(duì)調(diào)用的干擾。findMaxcomputepackage mainimport (    "context"    "fmt"    "math/rand"    "time")func findMax(ctx context.Context, concurrency int) uint64 {    var (        max uint64 = 0        num uint64 = 0    )    for i := 0; i < concurrency; i++ {        num = compute()        if num > max {            max = num        }    }    return max}func compute() uint64 {    // NOTE: This is a MOCK implementation of the blocking operation.        time.Sleep(time.Duration(rand.Int63n(100)) * time.Millisecond)    return rand.Uint64()}func main() {    maxDuration := 2 * time.Second    concurrency := 10    ctx, cancel := context.WithTimeout(context.Background(), maxDuration)    defer cancel()    max := findMax(ctx, concurrency)    fmt.Println(max)}https://play.golang.org/p/lYXRNTDtNCI當(dāng)我嘗試使用 goroutines 來重復(fù)調(diào)用函數(shù)時(shí)使用盡可能多的 goroutines，直到上下文被調(diào)用方函數(shù)取消。我每次都得到0，而不是灌漿計(jì)算函數(shù)調(diào)用的預(yù)期最大值。我嘗試了不同的方法來做到這一點(diǎn)，并且大部分時(shí)間都陷入僵局。findMaxcomputectxmainpackage mainimport (    "context"    "fmt"    "math/rand"    "time")func findMax(ctx context.Context, concurrency int) uint64 {    var (        max uint64 = 0        num uint64 = 0    )    for i := 0; i < concurrency; i++ {        select {        case <- ctx.Done():            return max        default:            go func() {                num = compute()                if num > max {                    max = num                }            }()        }    }    return max}func compute() uint64 {    // NOTE: This is a MOCK implementation of the blocking operation.        time.Sleep(time.Duration(rand.Int63n(100)) * time.Millisecond)    return rand.Uint64()}func main() {    maxDuration := 2 * time.Second    concurrency := 10    ctx, cancel := context.WithTimeout(context.Background(), maxDuration)    defer cancel()    max := findMax(ctx, concurrency)    fmt.Println(max)}https://play.golang.org/p/3fFFq2xlXAE