給定PHP中的2個(gè)數(shù)組，看起來(lái)像這樣...Array( [item1] => Array ( [myValues] => Array ( [1] => 5 [2] => 1 ) ) [item2] => Array ( [myValues] => Array ( [1] => 5 [2] => 1 ) ))Array( [item1] => Array ( [1] => 2 ) [item2] => Array ( [1] => 5 [2] => 1 ))array1array ( 'item1' => array ( 'myValues' => array ( 1 => 5, 2 => 1, ), ), 'item2' => array ( 'myValues' => array ( 1 => 5, 2 => 1, ), ), )將它們組合成如下所示的數(shù)組的最佳方法是什么？Array( [item1] => Array ( [myValues] => Array ( [1] => 5 [2] => 1 ) [myValues2] => Array ( [1] => 2 ) ) [item2] => Array ( [myValues] => Array ( [1] => 5 [2] => 1 ) [myValues2] => Array ( [1] => 5 [2] => 1 ) ))array2array ( 'item1' => array ( 1 => 2, ), 'item2' => array ( 1 => 5, 2 => 1, ), )我無(wú)法控制輸出，所以我認(rèn)為我最好的方法是遍歷每個(gè)數(shù)組并將項(xiàng)目復(fù)制到一個(gè)新的數(shù)組中。我試過(guò)了...print_r(array_merge($a1,$a2));但這并沒(méi)有給我?guī)?lái)我想要的結(jié)果。有人有例子嗎？
1 回答
慕森王
TA貢獻(xiàn)1777條經(jīng)驗(yàn) 獲得超3個(gè)贊
使用已知的第一級(jí)鍵和您發(fā)明的第二級(jí)鍵將 array2 數(shù)據(jù)推送到 array1 中。
代碼：（演示)
$array1 = array ( 'item1' => array ( 'myValues' => array ( 1 => 5, 2 => 1, ), ), 'item2' => array ( 'myValues' => array ( 1 => 5, 2 => 1, ), ), );
$array2 = array ( 'item1' => array ( 1 => 2, ), 'item2' => array ( 1 => 5, 2 => 1, ), );
foreach ($array2 as $key => $subarray) {
$array1[$key]['myValues2'] = $subarray;
}
var_export($array1);
輸出：
array (
'item1' =>
array (
'myValues' =>
array (
1 => 5,
2 => 1,
),
'myValues2' =>
array (
1 => 2,
),
),
'item2' =>
array (
'myValues' =>
array (
1 => 5,
2 => 1,
),
'myValues2' =>
array (
1 => 5,
2 => 1,
),
),
)
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