我有以下路線：Route::apiResource('payments', 'PaymentController', ['except' => ['store', 'destroy']]);Route::get('users/{user}/payments', [    'as' => 'users.payments',    'uses' => 'PaymentController@index',]);這個控制器：class PaymentController{    public function index(Request $request, User $user)    {        // Initialize query builder        $query = Payment::query();        // If a user was provided, return all payments belonging to that user        // if condition is satisfied        if ($user) {            if (condition) {                $query = $customer->payments();            } else {                // Some code that causes no results                $query->whereNull('id');   // <----- This hits the database            }        }        return PaymentResource::collection($query->paginate(10));    }}如果您點擊它，則應(yīng)返回所有用戶進行的所有付款。/payments如果命中它，則僅當(dāng)為 true 時，它才應(yīng)返回用戶進行的所有付款，否則應(yīng)返回空列表。/users/id/paymentscondition此代碼有效，但是是實際命中數(shù)據(jù)庫的解決方法。$query->whereNull('id');有沒有辦法避免命中數(shù)據(jù)庫并仍然返回空列表？