我想編寫一個(gè)小的幫助器函數(shù)來(lái)集中我的HTTP調(diào)用。來(lái)自Python，我仍然在Go中使用指針。幫助器函數(shù)實(shí)質(zhì)上采用帶有調(diào)用信息（URL，方法和可選請(qǐng)求正文）的a，并將響應(yīng)正文返回為（現(xiàn)在是）：struct[]bytenilpackage mainimport "net/http"type httpParameters struct {    Url string    Method func(client http.Client, string2 string) (*http.Response, error)    Body []byte}func callHTTP(param httpParameters) (resp []byte, err error) {    return nil, nil}附加的測(cè)試是package mainimport (    "net/http"    "testing")func TestCallHTTP(t *testing.T) {    params := httpParameters{        Url:    "https://postman-echo.com/get",        Method: http.Client.Get,    }    resp, err := callHTTP(params)    if err != nil {        t.Errorf("call to %v was not successful: %v", params.Url, err)    }    if resp != nil {        t.Errorf("GET call to %v returned something: %v, should be nil", params.Url, resp)    }}當(dāng)試圖運(yùn)行我得到.\main_test.go:11:22: invalid method expression http.Client.Get (needs pointer receiver: (*http.Client).Get)注意：在類型聲明中是一種試錯(cuò)法 - 我最終將內(nèi)容放在定義中。我不確定這是應(yīng)該引用這些功能的方式Method func(client http.Client, string2 string) (*http.Response, error)Get我應(yīng)該如何解決該方法以便能夠在調(diào)用中傳遞它？Get