我正在嘗試將結(jié)構(gòu)字段“Category”轉(zhuǎn)換為字符串，以便我可以在ConcatatenateNotification中進(jìn)行串聯(lián)。有人知道如何做嗎？請(qǐng)參閱下面的代碼片段。//Category is enum of//available notification types (semantic meaning of the notification)type Category string// Category allowed valuesconst ( FlowFailure Category = "flow_failure" WriterResult Category = "writer_result")//Notification is struct containing all information about notificationtype Notification struct { UserID int Category Category}//ConcatenateNotification loads data from Notification struct and concatenates them into one string, "\n" delimitedfunc ConcatenateNotification(n Notification) (msg string) { values := []string{} values = append(values, "UserID: " + strconv.Itoa(n.UserID)) values = append(values, "Category: " + (n.Category)) // Anybody knows how to convert this value to string? msg = strings.Join(values, "\n") return msg
2 回答
Qyouu
TA貢獻(xiàn)1786條經(jīng)驗(yàn) 獲得超11個(gè)贊
由于 已經(jīng)是底層，您可以簡(jiǎn)單地：Categorystring
values = append(values, "Category: " + string(n.Category))
萬(wàn)千封印
TA貢獻(xiàn)1891條經(jīng)驗(yàn) 獲得超3個(gè)贊
首先，你不需要strconv。Itoa 要將 int 與字符串連接起來(lái)，您可以簡(jiǎn)單地使用 .如有必要，您可以使用其他動(dòng)詞代替（此處更多）。您可以對(duì) . 是一種更習(xí)慣用的方式來(lái)連接go中的字符串。fmt.Sprintf("UserID:%v", n.UserID)%vCategoryfmt.Sprintf
因此，代碼將如下所示：
//ConcatenateNotification loads data from Notification struct
// and concatenates them into one string, "\n" delimited
func ConcatenateNotification(n Notification) (msg string) {
values := []string{}
values = append(values, fmt.Sprintf("UserID: %v", n.UserID))
values = append(values, fmt.Sprintf("Category: %v", n.Category))
msg = strings.Join(values, "\n")
return msg
}
如果你想縮短代碼，你也可以做這樣的事情：
func ConcatenateNotification(n Notification) (msg string) {
return fmt.Sprintf("UserID: %v\nCategory:%v", n.UserID, n.Category)
}
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