我希望在pygame中創(chuàng)建一個場景,但我似乎必須在每個子畫面和障礙物中單獨渲染,隨著場景變大,它變得有點......重復(fù)。 self.tree01 = Obstacles(config.tree01, 0, 10, self.player.group) self.tree02 = Obstacles(config.tree01, 1, 10, self.player.group) self.tree03 = Obstacles(config.tree01, 2, 10, self.player.group) self.tree04 = Obstacles(config.tree01, 3, 10, self.player.group) self.tree05 = Obstacles(config.tree01, 4, 10, self.player.group) self.tree06 = Obstacles(config.tree01, 5, 10, self.player.group) self.tree07 = Obstacles(config.tree01, 6, 10, self.player.group) self.tree08 = Obstacles(config.tree01, 7, 10, self.player.group) self.tree09 = Obstacles(config.tree01, 8, 10, self.player.group) self.tree10 = Obstacles(config.tree01, 9, 10, self.player.group) self.tree11 = Obstacles(config.tree01, 10, 10, self.player.group) self.tree12 = Obstacles(config.tree01, 11, 10, self.player.group) self.tree13 = Obstacles(config.tree01, 12, 10, self.player.group) self.tree14 = Obstacles(config.tree01, 13, 10, self.player.group) self.tree15 = Obstacles(config.tree01, 14, 10, self.player.group) self.tree16 = Obstacles(config.tree01, 15, 10, self.player.group) self.tree17 = Obstacles(config.tree01, 16, 10, self.player.group)這就是我當(dāng)前創(chuàng)建對象的方式,并且...這不可能是正確的。我的班級在這里。有沒有辦法以簡化的方式創(chuàng)建上述所有這些對象及其特定屬性?我曾想過在 for 循環(huán)中創(chuàng)建它們,但這并不能為它們提供單獨的屬性。class Obstacles(pygame.sprite.Sprite): def __init__(self,image, x, y, player): pygame.sprite.Sprite.__init__(self) self.image = image self.rect = self.image.get_rect() self.player = player self.rect.x = x * config.scale self.rect.y = y * config.scale self.check_collision = False self.rect.topleft = self.rect.x, self.rect.y self.groupObs = pygame.sprite.Group() self.groupObs.add(self) self.check_collide() def draw(self, screen): self.groupObs.draw(screen) self.rect.topleft = self.rect.x, self.rect.y
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炎炎設(shè)計
TA貢獻1808條經(jīng)驗 獲得超4個贊
您可以使用 a 或 a 來存儲您的屬性:list()
dict()
self.trees = [Obstacles(config.tree01, x, 10, self.player.group) for x in range(16)]
然后,您只需按索引訪問它們:而不是self.trees[5]
self.tree05
如果你不理解這個語法查找列表理解,它基本上是一個循環(huán),但更短。for
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