我有一個(gè)類，Packet我寫它來(lái)填充一個(gè)byte[]516 字節(jié)的數(shù)組。( ) 為 2 ，packetNum( ) 為 2， ( ) 為 512 。在我的類中有一個(gè)方法，它將這些屬性組合在一起以創(chuàng)建一個(gè)大小為 516 的數(shù)組，以發(fā)送給收件人：shortauthKeyshortaudiobyte[]Packetbyte[]public byte[] toByteArray() {    byte[] fullArray = new byte[516];    ByteBuffer packetNumBuffer = ByteBuffer.allocate(2);    packetNumBuffer.putShort(this.packetNum);    byte[] packetNumArray = packetNumBuffer.array();    ByteBuffer authKeyBuffer = ByteBuffer.allocate(2);    authKeyBuffer.putShort(this.authKey);    byte[] authKeyArray = authKeyBuffer.array();    System.arraycopy(packetNumArray, 0, fullArray, 0, packetNumArray.length);    System.arraycopy(authKeyArray, 0, fullArray, packetNumArray.length, authKeyArray.length);    System.arraycopy(this.audio, 0, fullArray, authKeyArray.length, this.audio.length);    return fullArray;}現(xiàn)在，在測(cè)試接收到的數(shù)據(jù)包時(shí)， my packetNum（在創(chuàng)建 next 之前遞增Packet）已成功傳輸 - 但是，authKeyandaudio完全錯(cuò)誤。這是我的代碼的輸出，它使用and創(chuàng)建了一個(gè)新Packet的：short authKey = 10short packetNum = 0Packet number: 0Auth key = -7936Packet number: 1Auth key = 19201Packet number: 2Auth key = 31490Packet number: 3Auth key = -1Packet number: 4Auth key = -2Packet number: 5Auth key = -3Packet number: 6Auth key = -4Packet number: 7Auth key = -3Packet number: 8Auth key = -2Packet number: 9Auth key = -1Packet number: 10Auth key = 8192auth 密鑰為每個(gè)數(shù)據(jù)包吐出隨機(jī)數(shù)，當(dāng)它應(yīng)該10用于所有數(shù)據(jù)包時(shí)。這使我相信我的方法沒有fullArray按預(yù)期填充我的方法。誰(shuí)能發(fā)現(xiàn)我做錯(cuò)了什么？