我有一本字典：new_members = {'member1': ['PCP2'], 'member10': ['PCP2'], 'member13': ['PCP5'], 'member2': ['PCP1', 'PCP2'], 'member5': ['PCP5'], 'member6': ['PCP1', 'PCP5'], 'member7': ['PCP2', 'PCP4'], 'member8': ['PCP5'], 'member9': ['PCP1', 'PCP5']}和 2 套：pcps_in_negative = {'PCP4'}pcps_at_zero = {'PCP6'}如果任一集合中的項(xiàng)目出現(xiàn)在任何字典的列表值中，請將其刪除。所以在這種情況下，應(yīng)該從“member7”列表中刪除“PCP4”。我試過了for k, v in new_members.items(): for i in v: if i in pcps_at_zero or i in pcps_in_negative: v.remove(i)但new_members項(xiàng)目保持不變?！癿ember7”應(yīng)該只有 ['PCP2']。這是一個(gè)簡單的例子。pcps_in_negative在另一種情況下，這些集合pcp_at_zero可能有更多項(xiàng)目。
2 回答
婷婷同學(xué)_
TA貢獻(xiàn)1844條經(jīng)驗(yàn) 獲得超8個(gè)贊
您可以從您的字典中過濾每個(gè)列表：
bad_items = pcps_in_negative | pcps_at_zero
new_members = {k: [e for e in v if e not in bad_items] for k, v in new_members.items()}
print(new_members)
輸出：
{'member1': ['PCP2'],
'member10': ['PCP2'],
'member13': ['PCP5'],
'member2': ['PCP1', 'PCP2'],
'member5': ['PCP5'],
'member6': ['PCP1', 'PCP5'],
'member7': ['PCP2'],
'member8': ['PCP5'],
'member9': ['PCP1', 'PCP5']}
九州編程
TA貢獻(xiàn)1785條經(jīng)驗(yàn) 獲得超4個(gè)贊
嘗試這個(gè) ：
import copy
for k, v in new_members.items():
temp_list = copy.deepcopy(v)
temp_list = [x for x in temp_list if x not in pcps_at_zero]
temp_list = [x for x in temp_list if x not in pcps_in_negative]
new_members[k] = temp_list
最終的 new_members 字典變?yōu)椋?/p>
{'member1': ['PCP2'],
'member10': ['PCP2'],
'member13': ['PCP5'],
'member2': ['PCP1', 'PCP2'],
'member5': ['PCP5'],
'member6': ['PCP1', 'PCP5'],
'member7': ['PCP2'],
'member8': ['PCP5'],
'member9': ['PCP1', 'PCP5']}
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