我有數(shù)據(jù)框，我需要使用 Python 查找前 20 個重復的句子，請讓我知道如何去做Column AHello How are you?This ticket is not validHow are things at you end?Hello How are you?How can I help you?Please help me with ticketsThis ticket is not validHello How are you?預(yù)期產(chǎn)出Column A Frequency of Repeated sentenceHello How are you? 3This ticket is not valid 2How can I help you? 1...到目前為止的代碼df = pd.read_csv("C:\\Users\\aaa\\abc\\Analysis\\chat.csv", encoding="ISO-8859-1") df['word_count'] = df['Column A'].apply(lambda x: len(str(x).split(" ")))df[['Column A','word_count']].head()for i, g in df.groupby('Column A'): print ('Frequency of repeating sentence : {}'.format(g['Column A'].duplicated(keep=False).sum()))我需要一個數(shù)據(jù)框中的結(jié)果，該數(shù)據(jù)框可以在最終結(jié)果中使用“A 列”和“頻率”列寫入 CSV
4 回答
郎朗坤
TA貢獻1921條經(jīng)驗 獲得超9個贊
這是一種使用方法.value_counts：
df['ColumnA'].value_counts()
要將其添加為列，您可以執(zhí)行以下操作：
df['Frequency'] = df['ColumnA'].map(df['ColumnA'].value_counts())
隔江千里
TA貢獻1906條經(jīng)驗 獲得超10個贊
嘗試這個：
df['count']=df.groupby(['ColumnA'] ).count()
df.sort_values(by='count', ascending=False)
print(df.head(20))
慕的地8271018
TA貢獻1796條經(jīng)驗 獲得超4個贊
df['count'] = df.groupby('Sentence')['Sentence'].transform('count')
df = df.sort_values(by = 'count', ascending = False)
df.head(20)
這將在原始數(shù)據(jù)框中添加一列“計數(shù)”，其中將包含相應(yīng)句子的頻率。transform()返回與原始數(shù)據(jù)框?qū)R的系列。
慕哥9229398
TA貢獻1877條經(jīng)驗 獲得超6個贊
df['count'] = df.groupby('Sentence')['Sentence'].transform('count')
df = df.sort_values(by = 'count', ascending = False)
df.head(20)
這將在原始數(shù)據(jù)框中添加一列“計數(shù)”，其中將包含相應(yīng)句子的頻率。transform()返回與原始數(shù)據(jù)框?qū)R的系列。
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