如何編寫 SWITCH 案例的代碼以給出 x 和 y 數(shù)值？x 和 y 在一個(gè)數(shù)組中。數(shù)組中的數(shù)據(jù)來自數(shù)據(jù)庫。<?php        $main_link = mysqli_connect('localhost', 'root', '','WMYC');        $a1 = mysqli_fetch_array(mysqli_query($main_link, "SELECT * FROM teams WHERE team='t1' AND round='r1'"));        $b1 = mysqli_fetch_array(mysqli_query($main_link, "SELECT * FROM teams WHERE team='t2' AND round='r1'"));        $c1 = mysqli_fetch_array(mysqli_query($main_link, "SELECT * FROM teams WHERE team='t3' AND round='r1'"));        $d1 = mysqli_fetch_array(mysqli_query($main_link, "SELECT * FROM teams WHERE team='t4' AND round='r1'"));        $array = array($a1['xy'], $b1['xy'], $c1['xy'], $d1['xy']);        print_r($array); // will get Array ( [0] => x [1] => y [2] => x [3] => x )         print_r(array_count_values($array)); // will get Array ( [x] => 3 [y] => 1 )    switch(isset($_POST['round1']))    {            case //array_count_values($array) == ( [x] => 3 [y] => 1 ):          //value of x = 1 and value of y= -3            break;            case //array_count_values($array) == ( [x] => 2 [y] => 2 ):          //value of x = 2 and value of y= -2            break;            case //array_count_values($array) == ( [x] => 1 [y] => 3 ):          //value of x = 3 and value of y= -1            break;            case //array_count_values($array) == ( [x] => 4 ):          //value of x = -1            break;            case //array_count_values($array) == ( [y] => 4 ):          //value of y = 1    }        ?>如果有比 switch case 更好更簡(jiǎn)單的方法請(qǐng)指教