我在一個(gè)數(shù)據(jù)庫中有 2 個(gè)表，我正在加入一個(gè) PDO 執(zhí)行，我讓它以一種表的形式輸出，但我需要它以另一種格式。我需要某種形式的動(dòng)態(tài)支點(diǎn)嗎？2張桌子是這樣的：我希望從中得到下表：我用來整理數(shù)據(jù)的當(dāng)前查詢是：$sql3 = $pdo->prepare('SELECT b.title, a.nameFROM poll_summary a INNER JOIN poll_answers b ON a.answers_id = b.id WHERE a.poll_id = ? ORDER BY title');$sql3->execute([$_GET['id']]);$testing = $sql3->fetchAll(\PDO::FETCH_GROUP|\PDO::FETCH_ASSOC); 這是它給出的示例數(shù)組：Array ( [Knight ] => Array ( [0] => Array ( [name] => Dave ) [1] => Array ( [name] => Simon ) ) [Lieutenant ] => Array ( [0] => Array ( [name] => Tom ) ) )我可以使用以下方法從標(biāo)題列中獲取表頭：<table border=1> <thead> <tr> <?php foreach($testing as $key => $val): ?> <th><?php echo $key;?></th> <?php endforeach; ?> </tr> </thead> <tbody> <tr> </tbody></table>但我不知道如何將名稱值放入正確的列中。我嘗試使用此代碼，但無法讓它按我想要的方式工作。foreach($testing as $key => $val) { $arrlength = count($val); for($x = 0; $x < $arrlength; $x++) { //echo $key; echo $key; echo $val[$x]['name']; }}輸出：Knight Dave Knight Simon Lieutenant Tom
1 回答
茅侃侃
TA貢獻(xiàn)1842條經(jīng)驗(yàn) 獲得超22個(gè)贊
在 $testing 中已經(jīng)有了這個(gè)結(jié)構(gòu)：
Array ( [Knight ] => Array ( [0] => Array ( [name] => Dave ) [1] => Array ( [name] => Simon ) ) [Lieutenant ] => Array ( [0] => Array ( [name] => Tom ) ) )
做表
<?php
// Just to keep same variable
$output = $testing;
?>
<table border=1>
<thead>
<tr>
<?php
// We need to know wich $title has more names
$max = 0;
foreach($output as $title => $names) {
if(count($names) > $max) {
$max = count($names);
}
?>
<th><?php echo $title;?></th>
<?php } // end foreach ?>
</tr>
</thead>
<tbody>
<?php
// Loop for creating table rows
for($i = 0; $i < $max; $i++) {
?>
<tr>
<?php
// Loop for creating table cells
foreach($output as $title => $names) {
?>
<td><?php
// Echo only if name exists
if(isset($names[$i]['name'])) {
echo $names[$i]['name'];
}
?></td>
<?php
} // end foreach
?>
</tr>
<?php
} // end for
?>
</tbody>
</table>
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