我可以使用一些幫助從結(jié)構(gòu)數(shù)組中找到所有高于計(jì)算平均值的數(shù)字！//MeanMedianMode structtype MeanMedianMode struct { numbers []float64}func main() { // range of numbers dataType := MeanMedianMode{ numbers: []float64{ 84, 25, 88, 56, 10, 19, 11, 80, 45, 83, 22, 40, 22, 52, 61, 13, 73, 23, //Data to be used 90, 89, 6, }, }我已經(jīng)弄清楚如何輕松傳遞我的數(shù)據(jù)并找到平均值如下......//CalcMean float64func (mm *MeanMedianMode) CalcMean() float64 { total := 0.0 for _, v := range mm.numbers { total += v } return (total / float64(len(mm.numbers))) //return math.Round(total / float64(len(mm.numbers))) //Should it need to be rounded}我最大的問(wèn)題是復(fù)制該過(guò)程并在另一個(gè)函數(shù)中使用存儲(chǔ)在數(shù)組中的值并迭代它們以找到大于（>）找到的平均值的值！我很欣賞這些見(jiàn)解！
1 回答
慕勒3428872
TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超6個(gè)贊
我不知道你想怎么做，但我猜是這樣的：
package main
import (
"fmt"
)
//MeanMedianMode struct
type MeanMedianMode struct {
numbers []float64
}
func main() {
m := &MeanMedianMode{
numbers: []float64{
84, 25, 88, 56, 10, 19, 11, 80,
45, 83, 22, 40, 22, 52, 61, 13, 73, 23,
90, 89, 6,
},
}
mean := m.CalcMean()
for _, n := range m.numbers {
if n > mean {
fmt.Printf("%.3f is greater than the mean\n", n)
}
}
}
//CalcMean float64
func (mm *MeanMedianMode) CalcMean() float64 {
total := 0.0
for _, v := range mm.numbers {
total += v
}
return (total / float64(len(mm.numbers)))
}
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