我正在編寫這個 PHP 程序，它將一條記錄插入一個名為事件的表中。PHP代碼是：<?php$servername = "example.com";$username = "dev";$password = "some password";$dbname = "mydb";$dateModified = gmdate("Y-m-d h:i:s a");// Create connection$conn = new mysqli($servername, $username, $password, $dbname);// Check connectionif ($conn->connect_error) {    die($conn -> connect_errno. " : ".$conn -> connect_error);}$sql = "INSERT INTO events (ID, eventName, timeStamp, dateModified)VALUES ('1', 'Login', 'Login', '12/12/2019',".$dateModified;if ($conn->query($sql) === TRUE) {    echo "New record created successfully";} else {    echo "Error: " . $sql . "<br>" . $conn->error;}$conn->close();?>我收到此錯誤：2002 : Connection timed out有趣的是，如果我將它包裝在一個函數(shù)中并嘗試相同的方法，則會出現(xiàn)此錯誤：1045 : Access denied for user ''@'localhost' (using password: YES)我哪里錯了？