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如果帶有 ageDifference 的語句未正確計算最接近的年齡

JavaScript

蝴蝶刀刀 2022-07-01 15:51:22

當我試圖找到年齡與 Sonya Sotomayor 最接近的人時，出了點問題。任何人都可以檢測到我的錯誤嗎？var notablePeople = { "Elvis Presley": new Date(1935, 0, 8), "Sonya Sotomayor": new Date(1954, 5, 25), "Franklin D. Roosevelt": new Date(1882, 0, 30), "Ben Carson": new Date(1951, 8, 18), "Roger Staubach": new Date(1942, 1, 5), "Steve Jobs": new Date(1955, 1, 24), "Albert Einstein": new Date(1879, 2, 14), "Isaac Asimov": new Date(1919, 9, 4), "Jada Pinkett Smith": new Date(1971, 8, 18), "Grace Hopper": new Date(1906, 11, 9), "Jared Nicholas": new Date(1995, 5, 16)};// Find who is closest in age to Sonya Sotomayorvar sonyaAge = notablePeople["Sonya Sotomayor"].getTime();var ageDifference = Infinity;var personClosest = "";for (person in notablePeople) { // See if this person's age difference is closer if (person != "Sonya Sotomayor" && Math.abs(notablePeople[person].getTime() - sonyaAge) < ageDifference) { ageDifference = Math.abs(notablePeople[person].getTime() - sonyaAge); ageDifference = ageDifference / 1000 / 60 / 60 / 24 / 365; personClosest = person; }}console.log("\nClosest age difference is " + person + " with " + ageDifference + " years difference.");輸出：/*This is not correct Closest age difference is Jared Nicholas with 19.473858447488585 years difference.*/

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3 回答

弒天下

TA貢獻1818條經(jīng)驗獲得超8個贊

var notablePeople = {

"Elvis Presley": new Date(1935, 0, 8),

"Sonya Sotomayor": new Date(1954, 5, 25),

"Franklin D. Roosevelt": new Date(1882, 0, 30),

"Ben Carson": new Date(1951, 8, 18),

"Roger Staubach": new Date(1942, 1, 5),

"Steve Jobs": new Date(1955, 1, 24),

"Albert Einstein": new Date(1879, 2, 14),

"Isaac Asimov": new Date(1919, 9, 4),

"Jada Pinkett Smith": new Date(1971, 8, 18),

"Grace Hopper": new Date(1906, 11, 9),

"Jared Nicholas": new Date(1995, 5, 16)

};

// Find who is closest in age to Sonya Sotomayor

var sonyaAge = notablePeople["Sonya Sotomayor"].getTime();

var ageDifference = Infinity;

var personClosest = "";

for (person in notablePeople) {

// See if this person's age difference is closer

console.log(person,Math.abs(notablePeople[person].getTime() - sonyaAge) / 1000 / 60 / 60 / 24 / 365);

if (person != "Sonya Sotomayor" && (Math.abs(notablePeople[person].getTime() - sonyaAge) < ageDifference)) {

ageDifference = Math.abs(notablePeople[person].getTime() - sonyaAge);

personClosest = person;

}

ageDifference = ageDifference / 1000 / 60 / 60 / 24 / 365;

console.log("\nClosest age difference is " + personClosest + " with " + ageDifference + " years difference.");

//您以錯誤的格式比較年齡，并且您使用的是 person 而不是 personClosest

反對回復 2022-07-01

慕妹3242003

TA貢獻1824條經(jīng)驗獲得超6個贊

我會用它reduce來解決這個問題。它的目的是獲取一個數(shù)組并將其減少為單個值。在這種情況下，我選擇將其簡化為包含姓名和年齡差異的對象。

var notablePeople = {

"Elvis Presley": new Date(1935, 0, 8),

"Sonya Sotomayor": new Date(1954, 5, 25),

"Franklin D. Roosevelt": new Date(1882, 0, 30),

"Ben Carson": new Date(1951, 8, 18),

"Roger Staubach": new Date(1942, 1, 5),

"Steve Jobs": new Date(1955, 1, 24),

"Albert Einstein": new Date(1879, 2, 14),

"Isaac Asimov": new Date(1919, 9, 4),

"Jada Pinkett Smith": new Date(1971, 8, 18),

"Grace Hopper": new Date(1906, 11, 9),

"Jared Nicholas": new Date(1995, 5, 16)

};

// Find who is closest in age to Sonya Sotomayor

var sonya = "Sonya Sotomayor";

var sonyaAge = notablePeople[sonya].valueOf();

var ageDifference = Infinity;

var personClosest = '';

// Object.keys returns an array of property names (the people)

var personAge = Object.keys(notablePeople)

// filter out Sonya

.filter(key => key !== sonya)

// go through the rest

.reduce((agg, cur) => {

// agg is the "aggregate value"; the object containing the name and age difference

// from the last loop.

// cur is the name of the person whose information we're looking at now

// calculate the difference between them. The difference is positive.

const diff = Math.abs(notablePeople[cur].valueOf() - sonyaAge);

// return an object with the difference (if it's less than any of the previous)

// and the name of the current person (again, if the difference is less than any of the previous)

return {

ageDifference: diff < agg.ageDifference ? diff : agg.ageDifference,

person: diff < agg.ageDifference ? cur : agg.person

}

},

// The initial value before any people have been examined

{

ageDifference,

person: ''

}

);

// get the age difference in years (approx)

personAge.ageDifference = personAge.ageDifference / 1000 / 60 / 60 / 24 / 365;

console.log(`Closest age difference is ${personAge.person} with ${personAge.ageDifference} years difference.`);

反對回復 2022-07-01

Qyouu

TA貢獻1786條經(jīng)驗獲得超11個贊

我通過基本的大小寫（簡化它）解決了這個問題，刪除了長除法并使用普通數(shù)字來檢查例程。這個問題很快就被發(fā)現(xiàn)了。您如何測試新的 ageDiff 無效。

底殼是一種非常有用的技術。這可能不是真正“技術上”是基本外殼，但概念是相同的；盡可能降低復雜性，您通?？梢愿p松地找到正在發(fā)生的事情。

看看下面。它呈現(xiàn)正確的結(jié)果（Staubach）。替換回你的邏輯（我自己，我會省略長除法，直到你已經(jīng)知道這個人是誰，如果你不確定你有合適的人，沒有理由運行這個邏輯），你應該能夠前進。

const notablePeople = {

"Elvis Presley": 50,

"Sonya Sotomayor": 30,

"Franklin D. Roosevelt": 10,

"Roger Staubach": 20,

"Ben Carson": 45,

};

console.log ( getPerson () );

function getPerson () {

let ageDiff = Infinity;

let finalPerson = null;

const sonyaAge = notablePeople["Sonya Sotomayor"];

for (person in notablePeople) {

if (person !== "Sonya Sotomayor") {

const testAgeDiff = Math.abs(notablePeople[person] - sonyaAge);

if ( testAgeDiff < ageDiff ) {

ageDiff = testAgeDiff;

finalPerson = person;

}

return finalPerson;

}

我在這里提出的另一個提示；我故意確保我期望的目標不是列表中的最后一個條目?？吹介_發(fā)人員編寫這樣的邏輯并不少見，他們運行測試并得到預期的結(jié)果，所以他們認為沒問題。如果目標是已檢查集合中的最后一個條目，那么您真的不知道您是否得到了正確的答案，或者您是否只是返回集合中的最后一個條目。我移動了數(shù)字，總是得到我期望的結(jié)果。

請注意，這不會執(zhí)行您的代碼應該執(zhí)行的檢查相同年齡、無效年齡等操作。但我認為通過這里的程序，你會看到邏輯錯誤并得到想法。

最后一點；這也可以使用 Array.filter 來完成，并且您可以使其整體更簡潔。可能值得研究一下。在這里，我想盡可能地貼近您的原始想法，以便您可以看到邏輯炸彈。

反對回復 2022-07-01