我有一個(gè).properties文件，其中包含一組屬性作為鍵值對(duì)。這被讀入配置枚舉類。此配置類包含對(duì)應(yīng)于屬性的枚舉。我希望能夠發(fā)現(xiàn)兩者之間的差異。因此，如果屬性文件包含類中不存在的屬性，或者相反。換句話說，我有一個(gè)枚舉數(shù)組：MyEnumClass[] enums = {E1,E2,E3}和一個(gè)表示枚舉的字符串?dāng)?shù)組String[] properties = {"E1","E2","E3"}我怎樣才能找到兩者的交集？最好我想避免流。
2 回答
慕雪6442864
TA貢獻(xiàn)1812條經(jīng)驗(yàn) 獲得超5個(gè)贊
這是計(jì)算交集的簡單方法（更改輸入以使結(jié)果明顯）：
List<String> properties = Arrays.asList(new String[] { "E1", "E2" });
List<MyEnumClass> enums = Arrays.asList(new MyEnumClass[]
{ MyEnumClass.E2, MyEnumClass.E3 });
List<String> enumNames = new ArrayList<>();
for (MyEnumClass e : enums)
enumNames.add(e.name());
List<String> intersection = new ArrayList<>(enumNames);
intersection.retainAll(properties);
System.out.println(intersection); //[E2]
這可以計(jì)算彼此之間的差異：
List<String> propDiff = new ArrayList<>(properties);
propDiff.removeAll(enumNames);
System.out.println(propDiff); //[E1]
List<String> enumDiff = new ArrayList<>(enumNames);
enumDiff.removeAll(properties);
System.out.println(enumDiff); //[E3]
嚕嚕噠
TA貢獻(xiàn)1784條經(jīng)驗(yàn) 獲得超7個(gè)贊
你可以這樣使用EnumSet<MyEnumClass>：
Set<MyEnumClass> all = EnumSet.allOf(MyEnumClass.class);
EnumSet<MyEnumClass>然后從您的屬性創(chuàng)建另一個(gè)：
Set<MyEnumClass> loaded = EnumSet.noneOf(MyEnumClass.class);
for(String property : properties) {
loaded.add(MyEnumClass.valueOf(property));
}
Collection.removeAll然后，您可以使用, Collection.addAll,來檢查不同的內(nèi)容Collection.retainAll：
// all will now contain every element from loaded
all.addAll(loaded);
// all will now contain every element which was not contained in loaded
all.removeAll(loaded);
// all will now contain every element which was contained in loaded
all.retainAll(loaded);
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