我正在嘗試制作我的第一個(gè)程序，一個(gè)顯示遠(yuǎn)程服務(wù)器上所有開放端口的端口掃描器，我已經(jīng)讓它在 CLI 中工作（感謝互聯(lián)網(wǎng)），但決定制作一個(gè) GUI（Qt5）它。我希望 textbox2 在輸入 IP 地址并單擊“掃描！”后輸出所有打開的端口，顯然程序在單擊后不會(huì)崩潰。這是復(fù)制問題的相關(guān)代碼from PyQt5.QtWidgets import QMainWindow, QApplication, QWidget, QPushButton, QAction, QLineEdit, QMessageBox, QPlainTextEdit, QVBoxLayout, QLabelfrom PyQt5.QtGui import QIconfrom PyQt5.QtCore import pyqtSlot, Qtimport socketimport timeimport sysclass App(QMainWindow): def __init__(self): super().__init__() self.title = 'PPort' self.left = 10 self.top = 10 self.width = 800 self.height = 400 self.initUI() def initUI(self): self.setWindowTitle(self.title) self.setGeometry(self.left, self.top, self.width, self.height) self.label = QLabel('Enter Target Address:', self) self.label.move(50, -110) self.label.resize(300, 300) self.label2 = QLabel('Output:', self) self.label2.move(50, 80) self.label2.resize(300, 300) self.textbox = QLineEdit(self) self.textbox.move(50, 60) self.textbox.resize(540, 30) self.textbox2 = QPlainTextEdit(self) self.textbox2.move(50, 250) self.textbox2.resize(700, 100) self.textbox2.setReadOnly(True) self.button = QPushButton('Scan!', self) self.button.move(620, 60) self.button.clicked.connect(self.on_click) self.show()textbox2中沒有顯示錯(cuò)誤，令我感到奇怪的是，即使我self.textbox2.appendPlainText用print（）替換，它仍然沒有在vscode終端中輸出任何錯(cuò)誤消息。但是，輸入無效的 IP 地址會(huì)顯示 gaierror（無法解析主機(jī)），而不是在 textbox2 中，而是在終端中，與輸入有效 IP 地址（8.8.8.8、192.168.0.1）時(shí)它總是崩潰的情況相比. 我懷疑我使用 if/for/try 錯(cuò)誤地使其循環(huán)，但我真的看不出我做錯(cuò)了什么，因?yàn)槲規(guī)缀醪恢牢易鳛樾率衷谧鍪裁础?
1 回答
喵喔喔
TA貢獻(xiàn)1735條經(jīng)驗(yàn) 獲得超5個(gè)贊
for-loop 或 sleep 等耗時(shí)的任務(wù)會(huì)阻塞 GUI 事件循環(huán)，導(dǎo)致窗口凍結(jié)。在這些情況下，解決方案是在另一個(gè)線程中執(zhí)行該任務(wù)并通過信號(hào)在線程之間發(fā)送信息
import sys
import time
import socket
from functools import partial
from PyQt5.QtCore import pyqtSignal, pyqtSlot, QObject, QThread, QTimer
from PyQt5.QtWidgets import (
QApplication,
QGridLayout,
QLabel,
QLineEdit,
QMainWindow,
QPlainTextEdit,
QPushButton,
QWidget,
)
class SocketWorker(QObject):
messageChanged = pyqtSignal(str)
@pyqtSlot(str)
def start_task(self, ip):
socket.gethostbyname(ip)
try:
for port in range(0, 65536):
socketprofile = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = socketprofile.connect_ex((ip, port))
if result == 0:
self.messageChanged.emit("Port {} Is open".format(port))
socketprofile.close()
except socket.gaierror:
self.messageChanged.emit("Hostname could not be resolved")
time.sleep(5)
sys.exit()
except socket.error:
self.messageChanged.emit("Couldn't connect to server")
time.sleep(5)
sys.exit()
class App(QMainWindow):
def __init__(self):
super().__init__()
self.title = "PPort"
self.left = 10
self.top = 10
self.width = 800
self.height = 400
self.initUI()
def initUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.left, self.top, self.width, self.height)
self.textbox = QLineEdit()
self.button = QPushButton("Scan!")
self.textbox2 = QPlainTextEdit(readOnly=True)
central_widget = QWidget()
self.setCentralWidget(central_widget)
grid_layout = QGridLayout(central_widget)
grid_layout.addWidget(QLabel("Enter Target Address:"), 0, 0)
grid_layout.addWidget(self.textbox, 1, 0)
grid_layout.addWidget(self.button, 1, 1)
grid_layout.addWidget(QLabel("Output:"), 2, 0)
grid_layout.addWidget(self.textbox2, 3, 0, 1, 2)
self.button.clicked.connect(self.on_click)
thread = QThread(self)
thread.start()
self.socker_worker = SocketWorker()
self.socker_worker.moveToThread(thread)
self.socker_worker.messageChanged.connect(self.textbox2.appendPlainText)
@pyqtSlot()
def on_click(self):
textboxValue = self.textbox.text()
wrapper = partial(self.socker_worker.start_task, textboxValue)
QTimer.singleShot(0, wrapper)
if __name__ == "__main__":
app = QApplication(sys.argv)
ex = App()
ex.show()
sys.exit(app.exec_())
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