我需要使用 python 將日志文件轉(zhuǎn)換為字典格式show_pcs = 1 Po1(SU) Eth LACP Eth1/24(P) Eth2/24(P) Eth3/24/10(P) Eth4/24(P) 2 Po2(SU) Eth LACP Eth1/1/1(P) Eth1/1/2(P) Eth1/1/3(P) Eth1/1/4(P) Eth2/1/1(P) Eth2/1/2(P) Eth2/1/3(P) Eth2/1/4(P) 3 Po3(SD) Eth NONE --4 Po4(SD) Eth NONE --5 Po5(SD) Eth LACP Eth1/3/1(P) Eth1/3/2(P) Eth1/3/3(P) Eth101/3/4(D) Eth2/3/1(P) Eth2/3/2(P) Eth2/3/3(P) Eth2/3/4(D) 6 Po6(SU) Eth LACP Eth1/14/1(P) Eth1/14/2(P) Eth1/14/3(P) Eth1/14/4(P) Eth102/14/1(P) Eth2/14/2(P) Eth2/14/3(P) Eth2/14/4(P) 7 Po7(SD) Eth LACP Eth1/22(P) Eth2/22(P) Eth3/22(P) Eth107/1/22(D) 8 Po8(SU) Eth LACP Eth1/23(P) Eth2/23(P) Eth3/23(P)d_t = {}pattern_1= 'Po\d+'pattern_2='Eth\d+\/\d+(?:\/\d+)?\((?:P|D)\)'result_1 = re.findall(pattern_1,show_pcs)result_2 = re.findall(pattern_2,show_pcs)for p1 in result_1: for p2 in result_2: d_t[result_1] = result_2print(d_t){ 'Po1' : ['Eth1/24(P)', 'Eth2/24(P)', 'Eth3/24/10(P)','Eth4/24(P)'], 'Po2': ....}
2 回答
弒天下
TA貢獻(xiàn)1818條經(jīng)驗 獲得超8個贊
show_pcs = '''
1 Po1(SU) Eth LACP Eth1/24(P) Eth2/24(P) Eth3/24/10(P)
Eth4/24(P)
2 Po2(SU) Eth LACP Eth1/1/1(P) Eth1/1/2(P) Eth1/1/3(P)
Eth1/1/4(P) Eth2/1/1(P) Eth2/1/2(P)
Eth2/1/3(P) Eth2/1/4(P)
3 Po3(SD) Eth NONE --
4 Po4(SD) Eth NONE --
5 Po5(SD) Eth LACP Eth1/3/1(P) Eth1/3/2(P) Eth1/3/3(P)
Eth101/3/4(D) Eth2/3/1(P) Eth2/3/2(P)
Eth2/3/3(P) Eth2/3/4(D)
6 Po6(SU) Eth LACP Eth1/14/1(P) Eth1/14/2(P) Eth1/14/3(P)
Eth1/14/4(P) Eth102/14/1(P) Eth2/14/2(P)
Eth2/14/3(P) Eth2/14/4(P)
7 Po7(SD) Eth LACP Eth1/22(P) Eth2/22(P) Eth3/22(P)
Eth107/1/22(D)
8 Po8(SU) Eth LACP Eth1/23(P) Eth2/23(P) Eth3/23(P)
'''
l = [i.strip() for i in show_pcs.split('\n') if len(i.strip())>0]
l = [j for i in l for j in i.split() if len(j)>0]
lst1 = []
lst = []
for i in l:
if i.isdigit():
if lst !=[]:
lst1.append(lst)
else:
lst=[i]
else:
lst.append(i)
dic = {i[1]:i[2:] for i in lst1}
print(dic)
輸出
{'Po1(SU)': ['Eth', 'LACP', 'Eth1/24(P)', 'Eth2/24(P)', 'Eth3/24/10(P)', 'Eth4/24(P)', 'Po2(SU)', 'Eth', 'LACP', 'Eth1/1/1(P)', 'Eth1/1/2(P)', 'Eth1/1/3(P)', 'Eth1/1/4(P)', 'Eth2/1/1(P)', 'Eth2/1/2(P)', 'Eth2/1/3(P)', 'Eth2/1/4(P)', 'Po3(SD)', 'Eth', 'NONE', '--', 'Po4(SD)', 'Eth', 'NONE', '--', 'Po5(SD)', 'Eth', 'LACP', 'Eth1/3/1(P)', 'Eth1/3/2(P)', 'Eth1/3/3(P)', 'Eth101/3/4(D)', 'Eth2/3/1(P)', 'Eth2/3/2(P)', 'Eth2/3/3(P)', 'Eth2/3/4(D)', 'Po6(SU)', 'Eth', 'LACP', 'Eth1/14/1(P)', 'Eth1/14/2(P)', 'Eth1/14/3(P)', 'Eth1/14/4(P)', 'Eth102/14/1(P)', 'Eth2/14/2(P)', 'Eth2/14/3(P)', 'Eth2/14/4(P)', 'Po7(SD)', 'Eth', 'LACP', 'Eth1/22(P)', 'Eth2/22(P)', 'Eth3/22(P)', 'Eth107/1/22(D)', 'Po8(SU)', 'Eth', 'LACP', 'Eth1/23(P)', 'Eth2/23(P)', 'Eth3/23(P)']}
慕尼黑5688855
TA貢獻(xiàn)1848條經(jīng)驗 獲得超2個贊
好吧，一種直接的方法是查看日志文件的結(jié)構(gòu)。如果Po鍵是第二個字符串，可以執(zhí)行以下操作：
log_line = '1 Po1(SU) Eth LACP Eth1/24(P) Eth2/24(P) Eth3/24/10(P)'
log_line_list = log_line.split() # will look like: ['1', 'Po1(SU)', 'Eth', ...]
k = log_line_list[1] # will hold 'Po1(SU)'
log_line_list.remove(k) # remove the key from the list
d = {k: log_line_list}
print(d)
>> {'Po1(SU)': ['1', 'Eth', 'LACP', 'Eth1/24(P)', 'Eth2/24(P)', 'Eth3/24/10(P)']}
你可以用一個方法來包裝它：
def dict_from_log(log_line):
l = log_line.split()
k = l[1]
l.remove(k)
return {k: l}
并遍歷您的日志行：map(dict_from_log, log_lines)
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