代碼如下：import requestsfrom bs4 import BeautifulSoupticker='FAST'url = "https://www.google.com/search?q=nasdaq+%s+earnings+reaction+history&tbs=qdr:m"%(ticker)response = requests.get(url)soup = BeautifulSoup(response.text, "html.parser")# for searchs in soup.find_all('div', {'class':'BNeawe s3v9rd AP7Wnd'}):cache = []for searchs in soup.find_all('div', {'class':'kCrYT'}): if searchs.find('a')['href'] is None: continue cache.append(searchs.find('a')['href']) print(''.join(cache))當(dāng) .find('a')['href'] 沒有返回結(jié)果時(shí)，我希望使用 if continue 語句來避免類型錯(cuò)誤。然而，它并沒有完成這項(xiàng)工作。有人可以指出克服它的方法嗎？
3 回答
翻閱古今
TA貢獻(xiàn)1780條經(jīng)驗(yàn) 獲得超5個(gè)贊
取決于你想用塊做什么，如果只有在href之后使用并使用后代組合select器指定具有子元素的父類和屬性href
import requests
from bs4 import BeautifulSoup
ticker='FAST'
url = "https://www.google.com/search?q=nasdaq+%s+earnings+reaction+history&tbs=qdr:m"%(ticker)
response = requests.get(url)
soup = BeautifulSoup(response.text, "html.parser")
cache = [searchs['href'] for searchs in soup.select('div.kCrYT [href]')]
print(''.join(cache))
Smart貓小萌
TA貢獻(xiàn)1911條經(jīng)驗(yàn) 獲得超7個(gè)贊
使用下面的代碼從TypeError.
try:
cache.append(searchs.find('a')['href'])
except TypeError:
continue
胡說叔叔
TA貢獻(xiàn)1804條經(jīng)驗(yàn) 獲得超8個(gè)贊
不要試圖在一行中放這么多：
...
for searchs in soup.find_all('div'):
tag = searchs.find('a')
#print(searchs)
if not tag:
continue
try:
h = tag['href']
except KeyError as e:
continue
print(h)
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