字典如下my = [{'Name':'Super', 'Gender':'Male', 'UNNO':111234}, {'Name':'Spider', 'Gender':'Male', 'UNNO':11123}, {'Name':'Bat', 'Gender':'Female', 'UNNO':113456}, {'Name':'pand', 'Gender':'Female', 'UNNO':13456}]唯一編號是每個字典的鍵“UNNO”的值。所有 UNNO 編號必須包含 6 位數(shù)字。UNNO 編號從 11 開始僅有效預(yù)計出局my_dict_list = {'Male':['Super'], 'Female':['Bat']}沒有正則表達(dá)式的原始代碼d = {}for i in my: if str(i['UNNO']).startswith('11') and len(str(i['UNNO'])) == 6: # To get {'Male':['Super'], 'Female':['Bat']} d[i['Gender']] = [i['Name']]如何借助regex寫，寫正則表達(dá)式，如何借助defaultdict完成import refrom collections import defaultdict# regular expressionrx = re.compile(r'^(?=\d{6}$)(?P<Male>11\d+)|(?P<Female>11\d+)')# output dictoutput = defaultdict(list)
1 回答
一只甜甜圈
TA貢獻(xiàn)1836條經(jīng)驗 獲得超5個贊
要使用正則表達(dá)式匹配來解決您的問題 - 使用以下方法：
import re
from collections import defaultdict
my_list = [{'Name': 'Super', 'Gender': 'Male', 'UNNO': 111234},
{'Name': 'Spider', 'Gender': 'Male', 'UNNO': 11123},
{'Name': 'Bat', 'Gender': 'Female', 'UNNO': 113456},
{'Name': 'pand', 'Gender': 'Female', 'UNNO': 13456}]
genders = defaultdict(list)
pat = re.compile(r'^11\d{4}$') # crucial pattern to validate `UNNO` number
for d in my_list:
if pat.search(str(d['UNNO'])):
genders[d['Gender']].append(d['Name'])
print(dict(genders)) # {'Male': ['Super'], 'Female': ['Bat']}
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