基于存儲在變量中的 XML 文件中的數(shù)據(jù)，$Xml我想創(chuàng)建一個具有自定義屬性的新數(shù)組。我確實從一個 foreach 循環(huán)開始：foreach($Xml->Sequences->Sequence as $var=>$value) { $MyObject[] = array( "title" => $value->SequenceName->__toString(), "folder" => true );}沒關系。結果如下所示：Array( [0] => Array ( [title] => Folder1 [folder] => 1 ) [1] => Array ( [title] => Folder2 [folder] => 1 ))該變量$Xml還包含子屬性，我需要將它們插入到我的新數(shù)組中。期望的結果是：Array( [0] => Array ( [title] => Folder1 [folder] => 1 [children] => Array ( [0] => Array ( [title] => Package1 ) ) ))我不知道如何得到這個結果！在我看來，我需要啟動另一個 foreach 循環(huán)來獲取子屬性并將它們存儲在循環(huán)中當前元素的數(shù)組中。我確實使用了這樣的代碼，但是創(chuàng)建了一個新節(jié)點并且它沒有存儲在父節(jié)點中。foreach($Xml->Sequences->Sequence as $var=>$value) { $MyObject[] = array( "title" => $value->SequenceName->__toString(), "folder" => true, ); foreach ($value->SequencePackages->Package as $a=>$b){ $MyObject[] = array( "children" => array(array( "title" => $b->PackageFolder->__toString(), )) ); }}我相信解決方案很簡單，但我無法獨自解決......謝謝您的支持。
3 回答
斯蒂芬大帝
TA貢獻1827條經驗 獲得超8個贊
建立新的數(shù)組數(shù)據(jù)并將其添加到最后而不是每個階段的主數(shù)組中會更容易......
$MyObject = [];
foreach($Xml->Sequences->Sequence as $var=>$value) {
$newObject =array(
"title" => $value->SequenceName->__toString(),
"folder" => true,
);
foreach ($value->SequencePackages->Package as $a=>$b){
$newObject["children"][] = ["title" => $b->PackageFolder->__toString()];
}
$MyObject[] = $newObject;
}
長風秋雁
TA貢獻1757條經驗 獲得超7個贊
用于創(chuàng)建數(shù)組的父循環(huán)的用戶索引。
$MyObject[$var] = array(
"title" => $value->SequenceName->__toString(),
"folder" => true
);
$MyObject[$var]['children'][] = array(array(
"title" => $b->PackageFolder->__toString(),
));
慕桂英546537
TA貢獻1848條經驗 獲得超10個贊
你需要做一些這樣的事情。您需要使用父數(shù)組中的鍵并插入新值子 foreach($Xml->Sequences->Sequence as $var=>$value) {
$MyObject[] = array(
"title" => $value->SequenceName->__toString(),
"folder" => true,
);
foreach ($value->SequencePackages->Package as $a=>$b){
$MyObject[‘children’] = array(
"title" => $b->PackageFolder->__toString(),
);
}
}
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