TA貢獻(xiàn)1780條經(jīng)驗(yàn) 獲得超1個(gè)贊
你可以這樣做。
測(cè)試數(shù)據(jù)：
create table tbl_cat (id int, cat_name varchar(32));
insert into tbl_cat(id, cat_name) values(1, "category1"), (2, "category2");
create table tbl_subcat (id int, cat_id int, subcat_name varchar(32));
insert into tbl_subcat(id, cat_id, subcat_name) values(1, 1, "subcat11"), (2, 1, "subcat12"), (3, 1, "subcat13"), (4, 2, "subcat21");
然后，PHP 腳本可以這樣寫：
<?php
$servername = "localhost";
$username = "your_user";
$password = "your_password";
$dbname = "test";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT cat_name, subcat_name FROM tbl_cat LEFT JOIN tbl_subcat ON tbl_cat.id = tbl_subcat.cat_id;";
$result = $conn->query($sql);
$last_category = "";
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$cat_name = $row["cat_name"];
if ($cat_name != $last_category) {
echo "Category: " . $cat_name .PHP_EOL;
$last_category = $cat_name;
}
echo "\tSubcategory: " . $row["subcat_name"] .PHP_EOL;
}
} else {
echo "0 results";
}
$conn->close();
?>
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