我有以下問題：有一個名為 的類UserConfigStorage，其中有 8 個字符串。程序第一次運行時，會要求用戶輸入他們的個人信息，這些信息存儲在上述 8 個字符串中。一旦用戶點擊一個按鈕，這個類就會被序列化和加密，以防止用戶修改它。然后，當程序第二次運行時，根據(jù)Form_Load事件，文件被解密，并使用反序列化方法將其中的信息加載到文本框。但是，System.Runtime.Serialization.SerializationException: End of Stream encountered before parsing was completed拋出異常，并且無法讀取文件。在查看代碼和生成的文件時，我發(fā)現(xiàn)生成的解密文件沒有所有信息。它實際上只存儲了 8 個字符串中的 6 個。方法如下：序列化方法 public void SerializeUserConfig(string fileName) { try { FileStream fileStream = new FileStream(fileName, FileMode.OpenOrCreate, FileAccess.ReadWrite); BinaryFormatter binForm = new BinaryFormatter(); binForm.Serialize(fileStream, userconfigstorage); fileStream.Close(); encryptor.Encrypt(fileName, perfilAcesso.GetUserConfigPath() + "Encrypted", "syndra15OP"); File.Delete(fileName); MessageBox.Show("Dados salvos com sucesso!"); } catch (Exception exception) { errorlog.SetError(exception.ToString()); SerializeError(perfilAcesso.GetUserErrorLogPath()); MessageBox.Show("Houve um erro ao salvar as configura??es!\nPor favor, contate o desenvolvedor.\n\nEID: 002"); } }反序列化方法 public UserConfigStorage DeserializeUserConfig(string fileName) { encryptor.Decrypt(perfilAcesso.GetUserConfigPath() + "Encrypted", fileName, "syndra15OP"); FileStream fileStream = new FileStream(fileName, FileMode.Open, FileAccess.Read); BinaryFormatter binForm = new BinaryFormatter(); UserConfigStorage userconfigstorage = (UserConfigStorage)binForm.Deserialize(fileStream); fileStream.Close(); return userconfigstorage; }任何人都可以幫助我了解導致文件未完全解密的原因嗎？提前致謝！
1 回答
白衣非少年
TA貢獻1155條經(jīng)驗 獲得超0個贊
是的，在這里使用絕對是您的朋友！:)
為什么要將對象序列化到一個文件中，只是為了在之后將其加密到另一個文件中？
我已經(jīng)清理了您的代碼，這應該可以按預期工作：
public void SerializeUserConfig(string fileName)
{
try
{
Encrypt(userconfigstorage, Path.Combine(perfilAcesso.GetUserConfigPath(), fileName), "syndra15OP");
MessageBox.Show("Dados salvos com sucesso!");
}
catch (Exception exception)
{
errorlog.SetError(exception.ToString());
SerializeError(perfilAcesso.GetUserErrorLogPath());
MessageBox.Show("Houve um erro ao salvar as configura??es!\nPor favor, contate o desenvolvedor.\n\nEID: 002");
}
}
public UserConfigStorage DeserializeUserConfig(string fileName)
{
return Decrypt(Path.Combine(perfilAcesso.GetUserConfigPath(), fileName), "syndra15OP");
}
public void Encrypt(UserConfigStorage input, string filePath, string strHash)
{
using (TripleDESCryptoServiceProvider tdc = new TripleDESCryptoServiceProvider())
{
using (FileStream outStream = new FileStream(filePath, FileMode.OpenOrCreate, FileAccess.Write))
{
using (MD5CryptoServiceProvider md5 = new MD5CryptoServiceProvider())
{
tdc.Key = md5.ComputeHash(ASCIIEncoding.ASCII.GetBytes(strHash));
md5.Clear();
}
tdc.Mode = CipherMode.ECB;
using (CryptoStream cryStream = new CryptoStream(outStream, tdc.CreateEncryptor(), CryptoStreamMode.Write))
{
BinaryFormatter binForm = new BinaryFormatter();
binForm.Serialize(cryStream, input);
}
}
}
}
public UserConfigStorage Decrypt(string filePath, string strHash)
{
UserConfigStorage output;
using (TripleDESCryptoServiceProvider tdc = new TripleDESCryptoServiceProvider())
{
using (FileStream outStream = new FileStream(filePath, FileMode.Open, FileAccess.Read))
{
using (MD5CryptoServiceProvider md5 = new MD5CryptoServiceProvider())
{
tdc.Key = md5.ComputeHash(ASCIIEncoding.ASCII.GetBytes(strHash));
md5.Clear();
}
tdc.Mode = CipherMode.ECB;
using (CryptoStream cryStream = new CryptoStream(outStream, tdc.CreateDecryptor(), CryptoStreamMode.Read))
{
BinaryFormatter binForm = new BinaryFormatter();
output = binForm.Deserialize(cryStream) as UserConfigStorage;
}
}
}
return output;
}
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