我正在使用 Python 為從 TextBlob 返回的結果分配標簽。我非?；镜拇a如下所示：from textblob import TextBlobdef sentLabel(blob): label = blob.sentiment.polarity if(label == 0.0): print('Neutral') elif(label > 0.0): print('Positive') else: print('Negative') Feedback1 = "The food in the canteen was awesome" Feedback2 = "The food in the canteen was awful" Feedback3 = "The canteen has food" b1 = TextBlob(Feedback1) b2 = TextBlob(Feedback2) b3 = TextBlob(Feedback3) print(b1.sentiment_assessments) print(sentLabel(b1)) print(b2.sentiment_assessments) print(sentLabel(b2)) print(b3.sentiment_assessments) print(sentLabel(b3))這會正確打印出情緒，但也會打印出“無”，如下所示：Sentiment(polarity=1.0, subjectivity=1.0, assessments=[(['awesome'], 1.0, 1.0, None)])PositiveNone...有什么辦法可以禁止打印“無”？感謝您的任何幫助或指點。
1 回答
三國紛爭
TA貢獻1804條經(jīng)驗 獲得超7個贊
你的函數(shù)sentLabelreturn None。因此，當您使用時print(sentLabel(b1))，它會打印None.
這應該適合你。
from textblob import TextBlob
def sentLabel(blob):
label = blob.sentiment.polarity
if(label == 0.0):
print('Neutral')
elif(label > 0.0):
print('Positive')
else:
print('Negative')
Feedback1 = "The food in the canteen was awesome"
Feedback2 = "The food in the canteen was awful"
Feedback3 = "The canteen has food"
b1 = TextBlob(Feedback1)
b2 = TextBlob(Feedback2)
b3 = TextBlob(Feedback3)
print(b1.sentiment_assessments)
sentLabel(b1)
print(b2.sentiment_assessments)
sentLabel(b2)
print(b3.sentiment_assessments)
sentLabel(b3)
添加回答
舉報
0/150
提交
取消